Problem 56
Question
Graph the solution set of each system of inequalities or indicate that the system has no solution. $$\left\\{\begin{array}{l}x^{2}+y^{2} \leq 16 \\\y<2^{x}\end{array}\right.$$
Step-by-Step Solution
Verified Answer
The solution to the system of inequalities is the region which lies inside the circle \(x^{2}+y^{2} \leq 16\) and below the curve \(y<2^{x}\). That is the overlapped region between the two graphs.
1Step 1: Understand and graph the inequalities separately
The inequality \(x^{2}+y^{2}\leq16\) depicts the area inside a circle, including its boundary. The center of the circle is the origin (0,0) and has a radius of 4. On the other hand, the graph \(y<2^{x}\) is the region below the graph of the exponential function y=2^x.
2Step 2: Identify the intersection of the two regions
The common area, i.e., the solution set of the system, lies in the intersection of the two regions described by the inequalities. Visually, this area represents points that satisfy both inequalities. It's the area inside the circle (and on the circle boundary) that is also below the exponential function.
3Step 3: Presenting the final Graph
The graph should highlight the intersection or common region that satisfies the given system of inequalities. This graphically represents all the ordered pairs that are solutions to the original system.
Key Concepts
Solution SetGraphical RepresentationExponential FunctionIntersection of Regions
Solution Set
When dealing with a system of inequalities, such as the given exercise, our task is to find the **solution set**. This is essentially the collection of all points that satisfy both inequalities simultaneously. In mathematical terms, it's a set of ordered pairs
- (x, y) values that make each inequality true.
- This might involve regions that fully or partially overlap.
The intersection of these regions, where both conditions are met, gives us the sought solution set.
Graphical Representation
**Graphical representation** helps visualize where solutions to the inequalities lie. By plotting each inequality separately on the same graph, you can easily see where they overlap.
- The circle \(x^2 + y^2 \leq 16\) is shown as a filled area with a boundary of radius 4 from the origin.
- The line \(y = 2^x\) represents the exponential curve, and the inequality \(y < 2^x\) covers everything below this curve.
Exponential Function
An **exponential function** like \(y = 2^x\) grows very quickly as \(x\) increases. It has some important properties that help us in graphing and problem-solving:
- This curve crosses the y-axis at (0,1), meaning it never touches or crosses the x-axis.
- As \(x\) gets larger, \(y\) increases rapidly, shooting upwards more steeply.
- The opposite is true as \(x\) becomes negative, where the curve approaches the x-axis, getting closer but never zero.
Intersection of Regions
To solve the system of inequalities, finding the **intersection of regions** is crucial. This is the area in the graph where both inequality conditions are simultaneously satisfied.
- This involves overlaying the circle defined by \(x^2 + y^2 \leq 16\) and the area beneath the curve \(y < 2^x\) on the same graph.
- The intersection gives us the **solution set** containing all (x, y) pairs fitting both criteria.
Other exercises in this chapter
Problem 56
Explain how to find the partial fraction decomposition of a rational expression with a prime quadratic factor in the denominator.
View solution Problem 56
Application Exercises A system for tracking ships indicates that a ship lies on a path described by \(2 y^{2}-x^{2}=1 .\) The process is repeated and the ship i
View solution Problem 57
Solve: $$\left\\{\begin{array}{r} A+B=3 \\ 2 A-2 B+C=17 \\ 4 A-2 C=14 \end{array}\right.$$
View solution Problem 57
Explain how to find the partial fraction decomposition of a rational expression with a repeated, prime quadratic factor in the denominator.
View solution