Problem 56
Question
Graph each equation. $$y-2.5=0$$
Step-by-Step Solution
Verified Answer
The graph of \(y - 2.5 = 0\) is a horizontal line plotted at y = 2.5 for all x-values.
1Step 1: Write the equation in general form
Rewrite the equation in the general form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Since there are no terms with x in the equation, it can be rewritten as \(y = 2.5\). This implies that the slope, m, is 0 and the y-intercept, b, is 2.5.
2Step 2: Interpret the result
Since the slope is 0 and the y-intercept is 2.5, the line to be plotted is a horizontal line running through the y-coordinates at 2.5, for all x-values.
3Step 3: Graph the line
To graph the line, identify the y-intercept at 2.5 and draw a straight, horizontal line across the graph at y = 2.5. This line will not slope upwards or downwards but lie flat, indicating that for any x-value, y will always be 2.5.
Key Concepts
Slope-Intercept FormHorizontal Line GraphY-Intercept
Slope-Intercept Form
In mathematics, the slope-intercept form is a powerful tool for understanding and graphing linear equations. This form is expressed as \(y = mx + b\), where \(m\) is the slope of the line and \(b\) is the y-intercept.
The slope \(m\) indicates the steepness of the line and its direction. However, in our given equation \(y = 2.5\), there is no \(x\) term, which means that \(m = 0\).
Hence, the line is horizontal, and you need not worry about rise or fall along the x-axis. The equation showcases how simple a line can be in its representation: a constant y-value that doesn't change.
Recognizing this form helps quickly identify how a line behaves, including its horizontal, vertical, or slanting nature. It also makes graphing lines fast and straightforward.
The slope \(m\) indicates the steepness of the line and its direction. However, in our given equation \(y = 2.5\), there is no \(x\) term, which means that \(m = 0\).
Hence, the line is horizontal, and you need not worry about rise or fall along the x-axis. The equation showcases how simple a line can be in its representation: a constant y-value that doesn't change.
Recognizing this form helps quickly identify how a line behaves, including its horizontal, vertical, or slanting nature. It also makes graphing lines fast and straightforward.
Horizontal Line Graph
A horizontal line graph is one of the simplest types of graphs you will encounter. It is a straight line drawn parallel to the x-axis without any incline or decline. In the equation \(y = 2.5\), the absence of an \(x\) term confirms this.
Horizontal lines can be easily identified by looking at their slope. When the slope \(m\) is 0, it indicates a constant y-value across all x-coordinates. This characteristic means that the line will remain flat and unchanging, no matter where you measure along the x-axis.
Horizontal lines can be easily identified by looking at their slope. When the slope \(m\) is 0, it indicates a constant y-value across all x-coordinates. This characteristic means that the line will remain flat and unchanging, no matter where you measure along the x-axis.
- Slope \(m = 0\): Indicates no change in height with change in x.
- Y-value is the same everywhere on the line.
- Run parallelly to the x-axis, appearing flat and steady.
Y-Intercept
The y-intercept is a concept intrinsic to understanding and plotting graphs. It represents the point where a line crosses the y-axis. In the slope-intercept form \(y = mx + b\), \(b\) denotes the y-intercept.
For our equation, \(y = 2.5\), the y-intercept is 2.5. This means that the line will touch the y-axis at the point (0, 2.5). It provides a starting spot on the graph when you begin plotting.
For our equation, \(y = 2.5\), the y-intercept is 2.5. This means that the line will touch the y-axis at the point (0, 2.5). It provides a starting spot on the graph when you begin plotting.
- The value of \(b\) directly shows where the line meets the y-axis.
- A higher \(b\) signifies a higher starting point on the y-axis.
- Allows visualization of lines, even without x-value calculations.
Other exercises in this chapter
Problem 56
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