Problem 56
Question
Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. Directrix: \(y=-1\)
Step-by-Step Solution
Verified Answer
The standard form of the parabola with directrix at \(y = -1\) and vertex at the origin is \(x^2 = -4y\).
1Step 1: Determine the direction of the Parabola
Since the directrix is \(y = -1\) and the vertex is the origin, it is clear that the parabola opens downwards. A downward opening parabola has the standard form of \(x^2 = -4ay\). The sign in front of the 4a tells us the direction of the opening.
2Step 2: Identify the focus and the directrix
Next, identify the focus and the directrix. Since the vertex is at the origin, and we know that the parabola is opening downwards, the focus will be at \(y = -a\). The directrix will be \(y = a\). Because the directrix is given as \(y = -1\), it can be concluded that \(a = 1\).
3Step 3: Create the Standard Form of The Equation
Now, substitute the value of \(a\) into the standard form of our equation \(x^2 = -4ay\). You get, \(x^2 = -4*1*y\), which simplifies to \(x^2 = -4y\).
Key Concepts
Standard FormDirectrixVertexFocus
Standard Form
The standard form of a parabola is essential to understanding its equation and orientation. It is given by the equation \[y = ax^2 + bx + c \] for parabolas opening up or down, or \[x = ay^2 + by + c \] for parabolas opening left or right.
In our exercise, since the parabola opens downwards, the applicable standard form becomes \[x^2 = -4ay \].
This specific form indicates:
In our exercise, since the parabola opens downwards, the applicable standard form becomes \[x^2 = -4ay \].
This specific form indicates:
- The parabola’s axis of symmetry is vertical.
- If the coefficient of \(x^2\) is negative, it opens downwards.
Directrix
The directrix of a parabola plays a pivotal role in defining its shape. It is a line parallel to the axis of symmetry of the parabola. The relationship between the directrix and the parabola dictates the proximity and orientation of the curve.
In our exercise, the directrix is given as \(y = -1\), which tells us that the parabola opens downwards.
This information:
In our exercise, the directrix is given as \(y = -1\), which tells us that the parabola opens downwards.
This information:
- Assists in determining the position of the vertex relative to the focus.
- Is essential in identifying the correct standard form of the equation.
Vertex
The vertex of a parabola is a point where the curve changes direction. It is considered the turning point and is either the highest or lowest point on the graph depending on the parabola's orientation.
In the given exercise, the vertex is at the origin (0, 0).
Knowing the vertex:
In the given exercise, the vertex is at the origin (0, 0).
Knowing the vertex:
- Helps in plotting the parabola precisely.
- Acts as a starting point for further calculations regarding the focus and directrix.
Focus
The focus of a parabola is a fixed point that, along with the directrix, helps in forming the shape of the curve. It is located inside the parabola and is equidistant from any point on the curve, when combined with the directrix.
From our standard equation \(x^2 = -4ay\), we can find the focus at point (0, -a). This exercise reveals that the focus lies at \(y = -1\), which makes \(a = 1\).
Knowing the focus:
From our standard equation \(x^2 = -4ay\), we can find the focus at point (0, -a). This exercise reveals that the focus lies at \(y = -1\), which makes \(a = 1\).
Knowing the focus:
- It helps in understanding how the parabola "wraps" itself around this point.
- Works together with the directrix to define the shape of the parabola.
Other exercises in this chapter
Problem 56
Use a graphing utility to graph the polar equation. Find an interval for \(\theta\) for which the graph is traced only once. $$r^{2}=25 \cos 2 \theta$$
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Use a graphing utility to graph the curve represented by the parametric equations. Folium of Descartes: \(x=\frac{3 t}{1+t^{3}}, y=\frac{3 t^{2}}{1+t^{3}}\)
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Convert the rectangular equation to polar form. Assume \(a
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Use a graphing utility to graph the curve represented by the parametric equations. Cycloid: \(x=\theta+\sin \theta, y=1-\cos \theta\)
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