Problem 56
Question
Find the product of the numbers $$ 10^{1 / 10}, 10^{2 / 10}, 10^{3 / 10}, 10^{4 / 10}, \ldots, 10^{19 / 10} $$
Step-by-Step Solution
Verified Answer
The product is \(10^{19}\).
1Step 1: Understanding the Problem
We need to find the product of a sequence of exponentiated numbers: \( 10^{1/10}, 10^{2/10}, \ldots, 10^{19/10} \).
2Step 2: Write the Product Expression
The product of the given terms is written as: \(10^{1/10} \times 10^{2/10} \times 10^{3/10} \times \ldots \times 10^{19/10}\).
3Step 3: Simplify Using Properties of Exponents
Using the property of exponents that allows us to add exponents when multiplying like bases, \(a^{m} \times a^{n} = a^{m+n}\), we can write this as \(10^{(1/10 + 2/10 + 3/10 + \ldots + 19/10)}\).
4Step 4: Calculate the Sum of the Exponents
The exponents form an arithmetic series: \(1/10, 2/10, \ldots, 19/10\). The sum of this series is \(\sum_{k=1}^{19}\frac{k}{10} = \frac{1}{10}(1+2+3+\ldots+19)\).
5Step 5: Calculate the Arithmetic Series
Use the formula for the sum of the first \(n\) natural numbers: \(\sum_{k=1}^{n}k = \frac{n(n+1)}{2}\). For \(n=19\), this is \(\frac{19 \times 20}{2} = 190\).
6Step 6: Complete the Simplification
Substitute the sum into the expression: \(\frac{190}{10} = 19\). Thus, the product simplifies to \(10^{19}\).
7Step 7: Final Conclusion
The product of the sequence \(10^{1/10}, 10^{2/10}, \ldots, 10^{19/10}\) is \(10^{19}\).
Key Concepts
Arithmetic SeriesProperties of ExponentsSum of Natural Numbers Formula
Arithmetic Series
An arithmetic series is a sequence of numbers in which each term after the first is obtained by adding a constant difference to the previous one. Think of it as a linearly growing series of numbers. For example, with a difference of 1, you would see terms like 1, 2, 3, and so on.
- In the context of our problem, the exponents form the arithmetic series \( \frac{1}{10}, \frac{2}{10}, \ldots, \frac{19}{10} \). These are increasing by \( \frac{1}{10} \) each step.
- This regular structure helps to simplify how we sum the terms, critical for simplifying expressions involving these terms.
Properties of Exponents
Exponents have several key properties that make them easier to work with. These rules help transform potentially complex expressions into more manageable forms.
- Product of Powers Property: When multiplying two powers with the same base, you simply add the exponents. For example: \( a^m \times a^n = a^{m+n} \).
- This simplifies exponential expressions significantly when you're dealing with sequences like the one in our problem as \(10^{1/10} \times 10^{2/10} \times \ldots = 10^{\text{sum of exponents}}\).
Sum of Natural Numbers Formula
The sum of natural numbers is a crucial formula that provides the total of all consecutive numbers up to a specific one:
- Formula: \( \sum_{k=1}^n k = \frac{n(n+1)}{2} \), where \( n \) is the last number in the series.
- In our exercise, we used this formula to find the sum of numbers from 1 to 19. This is because adding these numbers directly gives us the sum needed for our arithmetic series \(1 + 2 + 3 + \ldots + 19\).
- Once summed, this value helps simplify the exponentiation to \( \frac{190}{10} \) leading to a final expression of \( 10^{19} \).
Other exercises in this chapter
Problem 55
\(55-60\) . Write the sum without using sigma notation. $$ \sum_{k=1}^{5} \sqrt{k} $$
View solution Problem 55
Difference in Volumes of Cubes The volume of a cube of side \(x\) inches is given by \(V(x)=x^{3},\) so the volume of a cube of side \(X+2\) inches is given by
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Determine whether the infinite geometric series is convergent or divergent. If it is convergent, find its sum. $$ \frac{1}{3^{6}}+\frac{1}{3^{8}}+\frac{1}{3^{10
View solution Problem 56
\(55-60\) . Write the sum without using sigma notation. $$ \sum_{i=0}^{4} \frac{2 i-1}{2 i+1} $$
View solution