Problem 56
Question
Find the indicated term of each binomial expansion. \((u-2)^{7} ;\) fourth term
Step-by-Step Solution
Verified Answer
The fourth term of the binomial expansion \((u-2)^7\) is \(-280u^4\).
1Step 1: Determine n, k, a, and b
Given that the expression is \((u-2)^7\), we have:
n = 7 (exponent),
k = 4 (position of the term),
a = u (first element), and
b = -2 (second element).
2Step 2: Apply the binomial theorem formula
Now we apply the binomial theorem formula:
$$\text{term}_k = \binom{n}{k - 1} a^{n - (k - 1)} b^{k - 1}$$
We have already determined n, k, a, and b. Now we plug them into the formula:
$$\text{term}_4 = \binom{7}{4 - 1} u^{7 - (4 - 1)} (-2)^{4 - 1}$$
3Step 3: Calculate the term
Perform calculations:
$$\text{term}_4 = \binom{7}{3} u^{7 - 3} (-2)^{4 - 1}$$
$$\text{term}_4 = \binom{7}{3} u^{4} (-2)^{3}$$
Now, simplifying using binomial coefficient and solving for the powers of u and -2:
$$\text{term}_4 = 35 u^4 (-8)$$
Final step, multiply the binomial coefficient by the powers:
$$\text{term}_4 = -280 u^4$$
The fourth term of the binomial expansion \((u-2)^7\) is \(-280u^4\).
Other exercises in this chapter
Problem 55
Write each series using summation notation. 3+6+9+12
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Find \(S_{8}\) for each arithmetic sequence described below. $$a_{1}=10, d=-6$$
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Use the formula for \(S_{n}\) to find the sum of the terms of each geometric sequence. $$\frac{3}{8}, \frac{3}{2}, 6,24,96,384$$
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Write each series using summation notation. 4+8+12+16+20+24+28
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