Problem 56
Question
Find the asymptotes of the graph of each equation. $$ y=\frac{-2}{5-x}-6 $$
Step-by-Step Solution
Verified Answer
The vertical asymptote of the graph is at \(x = 5\), and the horizontal asymptote is at \(y = -6\).
1Step 1: Rewrite the Function
To make it easier to identify x-values at which the function is undefined, rewrite the function \(y=\frac{-2}{5-x}-6\) to the equivalent form \(y=\frac{-2}{x-5}-6\).
2Step 2: Identify Vertical Asymptotes
A vertical asymptote occurs at the x-values where the denominator of the function equals zero. To find the vertical asymptote, set x-5 equal to zero and solve for x. In this case, if you set \(x - 5 = 0\), it leads to \(x = 5\). So, the vertical asymptote is \(x = 5\).
3Step 3: Identify Horizontal Asymptotes
A horizontal asymptote is determined by comparing the degrees of the numerator and the denominator. In this case, the degree of the numerator is 0 and the degree of the denominator is 1. When the degree of the denominator is larger, the x-axis \(y = 0\) is the horizontal asymptote. However, in this case, there is a constant of \(-6\) added to the function, shifting it down by 6 units. So, the horizontal asymptote will be at \(y = -6\).
Key Concepts
Vertical AsymptotesHorizontal AsymptotesRational Functions
Vertical Asymptotes
Vertical asymptotes in a graph indicate where a function is undefined. These occur when the denominator of a rational function is zero. Solving the equation where the denominator equals zero helps pinpoint these vertical lines.
- For the function given, \( y = \frac{-2}{5-x} - 6 \), rewrite it as \( y = \frac{-2}{x-5} - 6 \) for clarity.
- Now set the denominator, \( x-5 \), equal to zero: \( x - 5 = 0 \).
- This simplifies to \( x = 5 \), establishing that the vertical asymptote is at \( x = 5 \).
Horizontal Asymptotes
Horizontal asymptotes describe the behavior of a function as it heads toward infinity either in the positive or negative direction on the x-axis. These lines suggest how a function behaves further away from the origin.
- To determine horizontal asymptotes, compare the degrees of the numerator and the denominator.
- In \( y = \frac{-2}{x-5} - 6 \), the numerator has a degree of 0 (a constant), while the denominator has a degree of 1.
- When the degree of the denominator is greater than the numerator, the horizontal asymptote is usually at \( y = 0 \).
- However, since there is a \(-6\) in the function, it adjusts the horizontal asymptote to \( y = -6 \).
Rational Functions
Rational functions come from dividing one polynomial by another. Understanding this helps in analyzing asymptotic behavior.
- The given function \( y = \frac{-2}{x-5} - 6 \) is an example of a rational function.
- The asymptotes in rational functions provide crucial insights into their graphs, indicating undefined points and long-term trends.
- Vertical asymptotes occur where the denominator equals zero, showing sharp disruptions in the graph.
- Horizontal asymptotes display the behavior of the function as x goes to infinity.
Other exercises in this chapter
Problem 56
Open-Ended Write a rational equation that has the following. a. one solution \(\quad\) b. two solutions \(\quad\) c. no real solution
View solution Problem 56
Find the least common multiple of \(x^{2}-1\) and \(x^{2}-x\). A. \(x-1\) B. \(x(x-1)(x+1)\) C. \(x(x-1)^{2}(x+1)\) D. \((x-1)^{2}(x+1)^{2} x^{2}\)
View solution Problem 56
What are the asymptotes of the graph of \(y=\frac{10}{x-5} ?\) F. \(x=0, y=5\) G. \(x=5, y=5\) H. \(x=5, y=10\) J. \(x=10, y=5\)
View solution Problem 56
Writing. Explain why 0 cannot be in the domain of an inverse variation.
View solution