Problem 56
Question
Find each product. $$(x-1)^{3}$$
Step-by-Step Solution
Verified Answer
The product of \( (x-1)^3 \) is \( x^3 - 3x^2 + 3x - 1 \).
1Step 1: Understand the Binomial Theorem
The Binomial Theorem tells us how to expand expressions of the form \( (a + b)^n \), where \( n \) is a natural number. For \( (x - 1)^3 \), this means expanding out \( (x - 1)(x - 1)(x - 1) \).
2Step 2: Perform Multiplication
Start by multiplying the first two expressions, \( (x - 1)(x - 1) \), and then, multiply the result by the third expression. Therefore, done incrementally: First, \( (x - 1)(x - 1) = x^2 - 2x + 1 \), then we multiply this by \( (x - 1) \), which gives \( (x^2 - 2x + 1)(x - 1) \).
3Step 3: Distribution of terms
Distribute terms by multiplying each term in the expression \( (x^2 -2x +1) \) by \( (x-1) \). This gives us \( x^3 - 2x^2 + x - x^2 + 2x - 1 = x^3 - 3x^2 + 3x - 1 \).
Other exercises in this chapter
Problem 56
Factor each perfect square trinomial. $$ 64 x^{2}-16 x+1 $$
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Evaluate each expression or indicate that the root is not a real number. $$\sqrt[3]{8}$$
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Add or subtract as indicated. $$\frac{x+5}{x^{2}-4}-\frac{x+1}{x-2}$$
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Simplify each exponential expression in Exercises 23–64. $$\left(10 x^{2}\right)^{-3}$$
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