Problem 56
Question
Find an equation of the line that goes through the given point and has the given slope. Give the answer in slope-intercept form. See Example 5 (-3, -1) with slope 6
Step-by-Step Solution
Verified Answer
The equation is \( y = 6x + 17 \).
1Step 1: Identify the point and slope
The point given is (-3, -1) and the slope is 6.
2Step 2: Understand the slope-intercept form
The slope-intercept form of a line is given by the equation: \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
3Step 3: Substitute the slope and point into the slope-intercept form
Use the given slope (6) and the coordinates of the given point (-3, -1) to write the equation: Substitute \( m = 6 \), \( x = -3 \), and \( y = -1 \) into the equation \( y = mx + b \): -1 = 6(-3) + b
4Step 4: Solve for the y-intercept \( b \)
Calculate \( 6(-3) \): -1 = -18 + b Add 18 to both sides to isolate \( b \): -1 + 18 = b So, \( b = 17 \)
5Step 5: Write the final equation
Substitute \( m = 6 \) and \( b = 17 \) back into the slope-intercept form equation: \( y = 6x + 17 \)
Key Concepts
Linear EquationsCalculating y-interceptSlope and Points
Linear Equations
Linear equations describe straight lines on a graph. The standard equation for a straight line is represented in the slope-intercept form: \[ y = mx + b \]. In this equation, \( m \) stands for the slope of the line, and \( b \) stands for the y-intercept, the point where the line crosses the y-axis.Understanding linear equations makes it easier to plot relationships between variables on a graph. These are foundational in algebra and come in handy when solving real-world problems involving constant rates of change or linear relationships.
Calculating y-intercept
The y-intercept (\( b \)) is the value of \( y \) where the line intersects the y-axis. This happens when \( x = 0 \). Here's how you can find it:
- Start with the slope-intercept form equation: \( y = mx + b \).
- Substitute a given point on the line (\( x, y \)) and the slope (\( m \)) into the equation.
- Solve for \( b \) by isolating it on one side of the equation.
- Substitute into the formula: \( -1 = 6(-3) + b \).
- Simplify the equation:\( -1 = -18 + b \).
- Solve for \( b \): \( -1 + 18 = b \), so \( b = 17 \).
Slope and Points
The slope (\( m \)) measures the steepness of a line and is calculated as the ratio of the 'rise' (vertical change) over the 'run' (horizontal change) between two points on the line. If you have a point (\( x_1, y_1 \)) and the given slope \( m \), you can easily set up your linear equation:
- Start with the formula: \( y = mx + b \).
- Input the values for \( x \) and \( y \) from the point into the formula along with \( m \).
- Solve for \( b \) as explained in the previous section.
- Finally, substitute \( m \) and \( b \) back into the slope-intercept form: \( y = 6x + 17 \).
Other exercises in this chapter
Problem 55
Find the \(x\) - and \(y\) -intercepts for each line and use them to graph the line. $$y=2 x-4$$
View solution Problem 55
Determine whether the lines \(l_{1}\) and \(l_{2}\) are parallel, perpendicular, or neither. In goes through \((0,2)\) and \((7,9), l_{2}\) goes through \((0,-3
View solution Problem 56
Find the \(x\) - and \(y\) -intercepts for each line and use them to graph the line. $$y=-3 x+6$$
View solution Problem 56
Determine whether the lines \(l_{1}\) and \(l_{2}\) are parallel, perpendicular, or neither. \(l_{1}\) goes through \((4,3)\) and \((2,6), l_{2}\) goes through
View solution