Problem 56
Question
Describe how to graph \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\)
Step-by-Step Solution
Verified Answer
The graph of the given equation is a hyperbola centered at (0,0) opening along the x-axis with vertices at (±3,0) and co-vertices at (0,±1). Its asymptotes are the lines \(y=±\frac{1}{3}x\).
1Step 1: Identifying Components
Identify the center, major axis and vertices from the given equation. In this case, the center is at the origin (0,0) because there's no translation in the equation. The a value or the semi-major axis is \(\sqrt{9}=3\) in the x direction and the b value or the semi-minor axis is \(\sqrt{1}=1\) in the y direction. Hence, the vertices are at points (±3,0).
2Step 2: Identify Co-Verticies
The co-vertices of the hyperbola can also be determined from the given equation by moving a distance 'b' in the y direction from the center. Hence, the co-vertices are at points (0,±1).
3Step 3: Draw Asymptotes
The asymptotes of the hyperbola are the diagonals of the rectangle formed by vertices and co-vertices. The equation of asymptotes in this case will be \(y=±\frac{b}{a}x=±\frac{1}{3}x\). Plot these lines on graph.
4Step 4: Sketch the Hyperbola
Since this is a horizontal hyperbola (as the x term is positive), draw the hyperbola opening left and right through the vertices, approaching the asymptotes as it moves away from the center.
Other exercises in this chapter
Problem 55
What is a hyperbola?
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Convert each equation to standard form by completing the square on \(x\) and \(y .\) Then graph the ellipse and give the location of its foci. $$4 x^{2}+25 y^{2
View solution Problem 57
Describe how to locate the foci of the graph of \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\)
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What is a parabola?
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