Problem 56
Question
Begin by graphing \(f(x)=\log _{2} x\). Then use transformations of this graph to graph the given function. What is the vertical asymptote? Use the graphs to determine each function's domain and range. $$ h(x)=2+\log _{2} x $$
Step-by-Step Solution
Verified Answer
The vertical asymptote for both graphs is x=0. The domain for both functions is \(x>0\). The range for the function \(f(x) = \log _{2}x\) is all real numbers, while for \(h(x)=2+\log _{2}x\), the range is all real numbers greater than 2.
1Step 1: Graphing f(x)
Start by graphing the parent function \(f(x)=\log _{2}x\). This function has a vertical asymptote at x=0 and passes through point (1,0). The domain for the function is all real numbers greater than 0, and its range is all real numbers.
2Step 2: Graphing h(x)
Next, graph the transformed function \(h(x)=2+\log _{2}x\). This function is a vertical shift of the parent function \(f(x)\), shifted 2 units upwards. This means every y-value of \(f(x)\) is increased by 2 in \(h(x)\). The vertical asymptote remains at x=0. The graph of \(h(x)\) passes through point (1,2). The domain for the function is all real numbers greater than 0 and its range is all real numbers greater than 2.
3Step 3: Comparing f(x) and h(x)
Comparing both functions, it can be seen that the vertical shift does not affect the vertical asymptote or the domain. The vertical asymptote remains at x=0, which is the line of undefined values for the log function. The domain for both functions is \(x>0\). The difference lies in the range - while the range of f(x) is all real numbers, the range of \(h(x)\) is all real numbers greater than 2 due to the upward shift.
Key Concepts
Logarithmic FunctionsVertical AsymptoteDomain and RangeVertical Shift
Logarithmic Functions
Logarithmic functions, like \(f(x) = \log_2{x}\), are the inverse of exponential functions. They are instrumental in solving problems related to growth and decay, such as in finance and nature. The function \(f(x) = \log_2{x}\) represents the power to which 2 must be raised to obtain \(x\). This means if \(f(x) = 3\), then \(x = 2^3 = 8\). Understanding their basic graph and transformations allows you to solve more complex real-world problems.
- The graph passes through the point (1,0) because \(\log_2{1} = 0\).
- The graph rises slowly and continues to rise indefinitely as \(x\) increases.
- For \(0 < x < 1\), the graph will fall sharply.
Vertical Asymptote
A vertical asymptote is a line that the graph of a function approaches but never touches or crosses. For logarithmic functions like \(f(x) = \log_2{x}\), the vertical asymptote is a direct consequence of the function's domain. Because logarithmic functions are only defined for positive real numbers, there is a vertical asymptote at \(x = 0\). Here:
- As \(x\) approaches 0 from the positive side, the value of \(f(x)\) decreases without bound, meaning it heads towards negative infinity.
- The vertical asymptote is a crucial feature as it indicates where the values of the function are undefined.
Domain and Range
Understanding the domain and range of a function is key to grasping its behavior and solving equations. The domain of \(f(x) = \log_2{x}\) is all positive real numbers, \(x > 0\), because the logarithm of zero or negative numbers is undefined. Meanwhile, its range is all real numbers because as \(x\) increases from 0 to infinity, \(f(x)\) covers all possible real output values.
- The domain remains \(x > 0\) even when transformations are applied, like in \(h(x) = 2 + \log_2{x}\).
- The range changes with transformations: the vertical shift modifies the range from all real numbers to all real numbers greater than a specific value.
Vertical Shift
A vertical shift in graph transformations refers to moving the graph up or down. This transformation changes only the y-values of the function, affecting the range but not the domain. For instance, transforming \(f(x) = \log_2{x}\) to \(h(x) = 2 + \log_2{x}\) shifts the graph 2 units upwards.
- Every point on \(f(x)\) moves exactly 2 units up to get \(h(x)\).
- The vertical asymptote at \(x = 0\) remains unchanged.
- The range of \(h(x)\) is now all real numbers greater than 2.
Other exercises in this chapter
Problem 55
Use the compound interest formulas \(A-P\left(1+\frac{r}{n}\right)^{n t}\) and \(A-P e^{n}\) to solve Exercises \(53-56 .\) Round answers to the nearest cent. S
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Solve each logarithmic equation in Exercises \(49-92 .\) Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions.
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In Exercises \(53-56,\) rewrite the equation in terms of base \(e\). Express the answer in terms of a natural logarithm and then round to three decimal places.
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In Exercises \(41-70,\) use properties of logarithms to condense each logarithmic expression. Write the expression as a single logarithm whose coefficient is \(
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