Problem 56
Question
An organic compound on heating with CuO produces \(\mathrm{CO}_{2}\) but not water. It may be (a) \(\mathrm{CH}_{4}\) (b) \(\mathrm{CCl}_{4}\) (c) \(\mathrm{CHCl}_{3}\) (d) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}\)
Step-by-Step Solution
Verified Answer
The compound is \( \text{CCl}_4 \) (carbon tetrachloride).
1Step 1: Understand the reaction requirement
The organic compound produces \( \text{CO}_2 \) but not water when heated with CuO. This means the compound must contain carbon but not hydrogen.
2Step 2: Analyze each compound
Examine each option to determine their elements: - \( \text{CH}_4 \) (methane) contains both C and H.- \( \text{CCl}_4 \) (carbon tetrachloride) contains only C and Cl.- \( \text{CHCl}_3 \) (chloroform) contains C, H, and Cl.- \( \text{C}_2 \text{H}_5 \text{I} \) (ethyl iodide) contains C, H, and Iodine.
3Step 3: Identify eligible compound
Since the compound must not contain hydrogen, only \( \text{CCl}_4 \) (carbon tetrachloride) fits the requirement. It contains carbon but no hydrogen, so it can produce \( \text{CO}_2 \) without forming water.
Key Concepts
Organic CompoundsCuO ReactionOxidation Reactions
Organic Compounds
Organic compounds are a wide category of chemicals mainly made from carbon atoms. Carbon's ability to form stable bonds with many elements, including itself, is why so many organic compounds exist.
Usually, these compounds also contain other elements such as hydrogen, oxygen, nitrogen, sulfur, and halogens (like chlorine and iodine).
The unique feature of carbon is its tetravalency, which means each carbon atom can form four covalent bonds with other atoms.
Usually, these compounds also contain other elements such as hydrogen, oxygen, nitrogen, sulfur, and halogens (like chlorine and iodine).
The unique feature of carbon is its tetravalency, which means each carbon atom can form four covalent bonds with other atoms.
- This allows the formation of long chains, branched structures, and rings.
- Common examples include hydrocarbons like methane (\(\text{CH}_4\)), and compounds with halogens such as carbon tetrachloride (\(\text{CCl}_4\)).
CuO Reaction
The reaction involving copper(II) oxide (CuO) is an important aspect of our exercise. CuO is often used as an oxidizing agent in organic chemistry.
When we heat an organic compound with CuO, it often helps in showing the presence or absence of certain elements.
During our exercise, CuO reacts with the carbon part of the compound to form carbon dioxide (\(\text{CO}_2\)). But for water (\(\text{H}_2\text{O}\)) to form, hydrogen must be present in the compound:
When we heat an organic compound with CuO, it often helps in showing the presence or absence of certain elements.
During our exercise, CuO reacts with the carbon part of the compound to form carbon dioxide (\(\text{CO}_2\)). But for water (\(\text{H}_2\text{O}\)) to form, hydrogen must be present in the compound:
- If a compound contains hydrogen, like methane or ethyl iodide, it would typically produce water when heated with CuO along with \(\text{CO}_2\).
- However, if a compound lacks hydrogen, such as carbon tetrachloride,\(\text{CO}_2\)will be produced without water.
Oxidation Reactions
Oxidation reactions involve the addition of oxygen or the removal of hydrogen from a substance. In our context, when organic compounds are oxidized, particularly with CuO, these reactions can result in the production of carbon dioxide and, if hydrogen is present, water.
In oxidation, each element has its oxidation state, which determines how electrons are gained or lost:
In oxidation, each element has its oxidation state, which determines how electrons are gained or lost:
- In the oxidation of compounds like carbon tetrachloride (\(\text{CCl}_4\)), only carbon is oxidized, forming carbon dioxide, since no hydrogen is available to create water.
- For compounds with hydrogen, both carbon and hydrogen interact with oxygen, leading to the formation of\(\text{CO}_2\)and\(\text{H}_2\text{O}\).
Other exercises in this chapter
Problem 53
An alkane has a C/H ratio of \(5.1428\) by mass. Its molecular formula is (a) \(\mathrm{C}_{5} \mathrm{H}_{12}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{14}\) (c) \(\m
View solution Problem 55
Which of the following compounds is violet in colour? (a) \(\mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN}), \mathrm{NSO}_{3}\right]_{3}\) (b) \(\mathrm{Na}_{3}\l
View solution Problem 57
The empirical formula of a compound is \(\mathrm{CH}_{2}\), One mole of the compound has a mass of \(42 \mathrm{~g}\). Its molecular formula is (a) \(\mathrm{C}
View solution Problem 59
\(60 \mathrm{~g}\) of a compound on analysis produced \(24 \mathrm{~g}\) carbon, \(4 \mathrm{~g}\) hydrogen and \(32 \mathrm{~g}\) oxygen. The empirical formula
View solution