Problem 55
Question
Write the first expression in terms of the second if the terminal point determined by \(t\) is in the given quadrant. \(\sin t, \cos t ; \quad\) Quadrant II
Step-by-Step Solution
Verified Answer
\( \sin t = \sqrt{1 - \cos^2 t} \) in Quadrant II.
1Step 1: Identifying Trigonometric Identities
In any quadrant, the sine and cosine functions are related by the identity \( \sin^2 t + \cos^2 t = 1 \). This identity will form the basis of our transformation.
2Step 2: Understanding Quadrant II Sign Convention
In Quadrant II, the sine function is positive, while the cosine function is negative due to the position relative to the axes. This means \( \sin t > 0 \) and \( \cos t < 0 \).
3Step 3: Expressing \(\sin t\) in terms of \(\cos t\)
We start with the Pythagorean identity: \( \sin^2 t + \cos^2 t = 1 \). Solving for \( \sin^2 t \), we get \( \sin^2 t = 1 - \cos^2 t \). Taking the square root, we have \( \sin t = \sqrt{1 - \cos^2 t} \), keeping the positive square root since \( \sin t > 0 \) in Quadrant II.
4Step 4: Final Relationship
Thus, the expression for \( \sin t \) in terms of \( \cos t \) in Quadrant II is \( \sin t = \sqrt{1 - \cos^2 t} \).
Key Concepts
Sine and Cosine FunctionsQuadrants in TrigonometryPythagorean Identity
Sine and Cosine Functions
The sine and cosine functions are fundamental in trigonometry and are represented by the symbols \(\sin t\) and \(\cos t\) respectively. They are defined using the unit circle, which is a circle with a radius of one, centered at the origin of the coordinate plane.
- Sine Function (\(\sin t\)): It measures the y-coordinate of an angle \(t\) on the unit circle.
- Cosine Function (\(\cos t\)): It measures the x-coordinate of an angle \(t\) on the unit circle.
Quadrants in Trigonometry
In trigonometry, the coordinate plane is divided into four quadrants. This helps to categorize angles based on their location, affecting the signs of sine and cosine functions.
- Quadrant I: Both \(\sin t\) and \(\cos t\) are positive.
- Quadrant II: \(\sin t\) is positive and \(\cos t\) is negative.
- Quadrant III: Both \(\sin t\) and \(\cos t\) are negative.
- Quadrant IV: \(\sin t\) is negative and \(\cos t\) is positive.
Pythagorean Identity
The Pythagorean identity is one of the most important identities in trigonometry. It connects the sine and cosine functions in a simple but powerful way:\[\sin^2 t + \cos^2 t = 1\]This equation is derived from the equation of a circle, \(x^2 + y^2 = r^2\), by setting the radius \(r = 1\) (the unit circle).
Applications of the Identity
The Pythagorean identity is instrumental in simplifying expressions and solving equations:- It allows us to express one trigonometric function in terms of another, as seen in the original exercise.
- If you know one value, say \(\cos t\), you can easily find \(\sin t\) using \(\sin^2 t = 1 - \cos^2 t\).
Other exercises in this chapter
Problem 54
From the information given, find the quadrant in which the terminal point determined by \(t\) lies. \(\cos t
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Find the period and graph the function. $$ y=2 \csc (3 x+3) $$
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(a) Prove that if \(f\) is periodic with period \(p,\) then 1\(/ f\) is also periodic with period \(p\) . (b) Prove that cosecant and secant each have period 2\
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Write the first expression in terms of the second if the terminal point determined by \(t\) is in the given quadrant. \(\cos t, \sin t ; \quad\) Quadrant IV
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