Problem 55
Question
Wing Shan just graduated from dental school owing \(\$ 80,000\) in student loans. The annual interest is \(6 \% .\) Her time \(t\) to pay off the loan is given by $$t=-\frac{\ln \left[1-\frac{80,000(0.06)}{n R}\right]}{n \ln \left(1+\frac{0.06}{n}\right)}$$ where \(n\) is the number of payment periods per year and \(R\) is the periodic payment. a. Use a graphing utility to graph $$t_{1}=-\frac{\ln \left[1-\frac{80,000(0.06)}{12 x}\right]}{12 \ln \left(1+\frac{0.06}{12}\right)} \text { as } Y_{1} \text { and }$$ $$t_{2}=-\frac{\ln \left[1-\frac{80,000(0.06)}{26 x}\right]}{26 \ln \left(1+\frac{0.06}{26}\right)} \text { as } Y_{2}$$ Explain the difference in the two graphs. b. Use the \([\text { TRACE }]\) key to estimate the number of years that it will take Wing Shan to pay off her student loan if she can afford a monthly payment of \(\$ 800\) c. If she can make a biweekly payment of \(\$ 400\), estimate the number of years that it will take her to pay off the loan. d. If she adds \(\$ 200\) more to her monthly or \(\$ 100\) more to her biweekly payment, estimate the number of years that it will take her to pay off the loan.