Problem 55
Question
What is the change in internal energy of a system if the system (a) absorbs \(58 \mathrm{J}\) of heat and does \(58 \mathrm{J}\) of work; (b) absorbs 125 J of heat and does 687 J of work; (c) evolves 280 cal of heat and has 1.25 kJ of work done on it?
Step-by-Step Solution
Verified Answer
The change in internal energy of the system are (a) 0J, (b) -562J, and (c) 2421.52J.
1Step 1: Calculate Internal Energy Change for Part (a)
Use the first law of Thermodynamics formula which is \( \Delta U = Q - W \), where \( \Delta U \) is the change in internal energy, Q is the heat absorbed by the system and W is the work done by the system. Substituting the given values, we get \( \Delta U = 58J - 58J = 0J \).
2Step 2: Calculate Internal Energy Change for Part (b)
Similarly for part (b), using the first law of Thermodynamics formula, \( \Delta U = Q - W \). Substitute the given values, \( \Delta U = 125J - 687J = -562J \). The negative sign indicates that energy has left the system.
3Step 3: Convert Calories to Joules for Part (c)
Given 1 cal = 4.184 J. So, 280 cal would be \( 280cal * 4.184 J/cal = 1171.52J \).
4Step 4: Calculate Internal Energy Change for Part (c)
Now, compute the change in internal energy for part (c). We need to remember that the work is done on the system this time, so it's considered negative. Converting work done from kJ to J (since 1 kJ = 1000 J), we get \( 1.25kJ * 1000 J/kJ = 1250J \). Hence, interior energy change is calculated as \( \Delta U = Q - W = 1171.52J - (-1250J) = 2421.52J \).
Key Concepts
Internal EnergyHeat AbsorptionWork Done on System
Internal Energy
When we talk about internal energy, we're referring to the total energy contained within a system. This includes the kinetic energy of molecules moving about and the potential energy associated with them. Internal energy is crucial in understanding how energy transfers affect a system.
One essential point is that the internal energy of a system can change due to exchanges of heat and work. If you ever find yourself wondering why a system feels hotter or colder, or why it seems to move with more or less vigor, it might be because its internal energy has shifted.
One essential point is that the internal energy of a system can change due to exchanges of heat and work. If you ever find yourself wondering why a system feels hotter or colder, or why it seems to move with more or less vigor, it might be because its internal energy has shifted.
- Increase in internal energy means the system becomes more energetic.
- Decrease in internal energy generally implies the system loses some energy to its surroundings.
Heat Absorption
Heat absorption is a critical concept when studying energy changes within a system. It is one way energy can be transferred into the system, causing a warming effect or fueling a reaction.
When a system absorbs heat:
When a system absorbs heat:
- The temperature of the system may increase, although in some cases, heat might cause changes in state without altering temperature.
- Potential energy within the system could increase, depending on the system's characteristics.
Work Done on System
The concept of work done on a system is another path by which energy can influence a system's internal energy. Whenever an external force performs work on a system, it essentially adds energy to it.
In thermodynamics:
In thermodynamics:
- If work is done on a system, this work is treated as negative in calculations because it adds energy to the system.
- If the system itself does work on its surroundings, this work is positive as it expends energy from the system.
Other exercises in this chapter
Problem 51
In each of the following processes, is any work done when the reaction is carried out at constant pressure in a vessel open to the atmosphere? If so, is work do
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In each of the following processes, is any work done when the reaction is carried out at constant pressure in a vessel open to the atmosphere? If so, is work do
View solution Problem 56
What is the change in internal energy of a system if the surroundings (a) transfer 235 J of heat and 128 J of work to the system; (b) absorb 145 J of heat from
View solution Problem 57
The internal energy of a fixed quantity of an ideal gas depends only on its temperature. A sample of an ideal gas is allowed to expand at a constant temperature
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