Problem 55
Question
Use a graphing utility to graph the function. Use the graph to determine whether the function has an inverse that is a function (that is, whether the function is one-to-one). $$f(x)=\frac{x^{4}}{4}$$
Step-by-Step Solution
Verified Answer
Upon graphing and applying the horizontal line test, it is observed that the function \(f(x)=\frac{x^{4}}{4}\) is not one-to-one as it fails the horizontal line test. Hence, the function \(f(x)=\frac{x^{4}}{4}\) does not have an inverse that is a function.
1Step 1: Graph the Function
Using a graphing utility, graph the function \(f(x)=\frac{x^{4}}{4}\). Ensure all relevant parts of the graph are included.
2Step 2: Apply the Horizontal Line Test
Draw horizontal lines through the graph. Check if any horizontal line intersects the graph at more than one point. If a horizontal line does intersect the graph at more than one point, then the function is not one-to-one, and subsequently, it does not have an inverse that is a function. If no horizontal line intersects the graph at more than one point, the function is one-to-one and it does have an inverse that is a function. The goal of this step is to see if the graph passes the horizontal line test.
3Step 3: Analyze the Result
Based on the result of Step 2, determine whether the function has an inverse that is a function. If the graph passes the horizontal line test, confirm that the function \(f(x)=\frac{x^{4}}{4}\) is one-to-one and it does have an inverse that is a function. If the graph does not pass the horizontal line test, then function does not have an inverse that is a function.
Other exercises in this chapter
Problem 55
Find the domain of each function. $$h(x)=\frac{7 x}{x^{2}-16}$$
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a. Rewrite the given equation in slope-intercept form. b. Give the slope and y-intercept. c. Graph the equation. $$2 x+3 y-18=0$$
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Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$x^{2}-2 x+y^{2}-15=0$$
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Find the average rate of change of the function from \(x_{1}\) to \(x_{2}.\) $$f(x)=3 x \text { from } x_{1}=0 \text { to } x_{2}=5$$
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