Problem 55
Question
Use a calculator to evaluate the expression. Round your answer to two decimal places. $$8.3+y^{3} \text { when } y=-4.6$$
Step-by-Step Solution
Verified Answer
The value of the given expression, after rounding to two decimal places, is -89.73.
1Step 1: Calculate the cube of y
Plug the value of y into the expression and calculate the cube of y. So you have \((-4.6)^3\). Use a calculator to find the result.
2Step 2: Sum with 8.3
Add the result from step 1 to the given number 8.3. Do the summation using a calculator.
3Step 3: Round to two decimal places
Round the result from step 2 to two decimal places.
Key Concepts
Expression EvaluationRounding NumbersCube of a Number
Expression Evaluation
In mathematics, solving an algebraic expression involves substituting numbers in place of variables, and then simplifying the calculation step-by-step. The expression given in the exercise is an example of this process: \(8.3 + y^3\), where \(y = -4.6\). To evaluate this expression, you need to follow a sequence of straightforward actions:
- First, substitute \(y\) with \(-4.6\) in the expression. This follows the basic rules of algebra where each variable is replaced with a given value.
- Next, simplify the expression by calculating powers and performing addition. Here, the key operation is finding the cube of \(y\).
Rounding Numbers
Once you arrive at a final number from the algebraic expression, the next task is to round it. Rounding is a method used to make a number simpler yet keeping it close to what it was. In the context of this exercise, we round the calculated result to two decimal places.
Here's how it's typically done:
- Look at the third decimal place (just after your desired two decimal places). This digit determines how you round the number.
- If the third decimal is 5 or greater, increase the second decimal by 1. Otherwise, leave the second decimal unchanged.
Cube of a Number
The cube of a number refers to multiplying the number by itself twice. Mathematically, it means \(y \times y \times y\) or \(y^3\). In the exercise, you encounter the task of cubing \(-4.6\). Calculating cubes is fundamental because it frequently appears across various fields of mathematics, physics, engineering, and computer algorithms. Important points to remember:
- When you cube a negative number, the result remains negative because multiplying three negative numbers still results in a negative product, given the laws of algebraic operations.
- Use a calculator to handle such computations for better accuracy, avoiding manual errors, especially with more complex or large numbers.
Other exercises in this chapter
Problem 55
A pest control company had a profit of \(\$ 3,514.65\) in April, a profit of \(\$ 5,674.25\) in May, a loss of \(\$ 8,992.88\) in June, and a loss of \(\$ 1,207
View solution Problem 55
Evaluate the expression. \(-29.4-(-8)+4\)
View solution Problem 55
Evaluate the expression for the given value(s) of the variable(s). $$\frac{15 x^{2}+10}{y} \text { when } x=-3 \text { and } y=\frac{2}{3}$$
View solution Problem 56
SIMPLIFYING EXPRESSIONS Simplify the expression by combining like terms. $$ \frac{7}{9} w+\left(-\frac{2}{3}\right) w $$
View solution