Problem 55
Question
The planets travel in elliptical orbits with the sun at one focus. Assume that the focus is at the pole, the major axis lies on the polar axis, and the length of the major axis is \(2 a\) (see figure). Show that the polar equation of the orbit is \(r=a\left(1-e^{2}\right) /(1-e \cos \theta),\) where \(e\) is the eccentricity.
Step-by-Step Solution
Verified Answer
The polar equation of the orbit is \(r=a(1-e^2) / (1-e\cos \theta)\)
1Step 1: Identify the Constants
Identify the given information: the major axis of the ellipse is of length \(2a\) and the eccentricity is \(e\). The sun, at one focus of the ellipse, is taken as the pole of the polar coordinate system.
2Step 2: Apply the Property of Ellipse
For any point P (r, \(\theta\)) on the ellipse, by the property of an ellipse, the sum of distances from the two foci (S and S') to that point P is constant and equal to the major axis. In terms of r, this can be expressed as: \(r + r' = 2a\). The distance r is the distance from the pole (S) to the point P, and r' from S' to the point P.
3Step 3: Relate Distances with Eccentricity
The eccentricity of the ellipse is defined as the ratio of the distance between the foci to the length of the major axis. This can be expressed as \(e = SS' / 2a\). With the sun at the origin, the distance SS' is also \(2ae\). Therefore, the distance from S' to a point P can also be expressed in terms of r and \(\theta\) as: \(r' = 2ae + r \cos \theta\).
4Step 4: Substitution into Original Equation
Substitute \(r'\) from Step 3 into \(r + r' = 2a\) from Step 2 to obtain: \(r + 2ae + r \cos \theta = 2a\). Simplifying this equation leads to: \(r = a(1 - e\cos \theta) / (1 - e^2)\)
Key Concepts
EccentricityEllipse PropertiesPolar CoordinatesOrbital Motion
Eccentricity
Eccentricity is a fundamental concept when discussing ellipses and their shapes. It is a parameter that measures how much an ellipse deviates from being a perfect circle. The eccentricity is represented by the symbol \( e \).
The value of \( e \) ranges between 0 and 1 for an ellipse. When \( e = 0 \), the ellipse is actually a circle because the two foci are at the same point. As \( e \) approaches 1, the ellipse becomes more stretched and elongated.Understanding eccentricity can help describe different types of orbits and shapes:
This is crucial for studying how planets and other celestial bodies move around stars.
The value of \( e \) ranges between 0 and 1 for an ellipse. When \( e = 0 \), the ellipse is actually a circle because the two foci are at the same point. As \( e \) approaches 1, the ellipse becomes more stretched and elongated.Understanding eccentricity can help describe different types of orbits and shapes:
- If \( e = 0 \), it is a circle.
- If \( 0 < e < 1 \), it is an ellipse.
- An eccentricity of exactly 1 or greater would describe a parabolic or hyperbolic trajectory, not an ellipse.
This is crucial for studying how planets and other celestial bodies move around stars.
Ellipse Properties
An ellipse is a closed curve, which can be thought of as a stretched circle. It has several unique properties that make it interesting in geometry and astronomy.
In mathematics, an ellipse is defined as the set of points in a plane where the sum of the distances to two fixed points, called foci, is constant.Key properties of an ellipse include:
In mathematics, an ellipse is defined as the set of points in a plane where the sum of the distances to two fixed points, called foci, is constant.Key properties of an ellipse include:
- Major Axis: This is the longest diameter of the ellipse, stretching from one side of the ellipse to the other through both foci. Its length is usually represented as \( 2a \).
- Minor Axis: This is the shortest diameter, perpendicular to the major axis.
- Foci: These are the two special points along the major axis. In the context of an orbital path, one focus is occupied by the central body (like the sun).
Polar Coordinates
Polar coordinates provide an alternative way of describing the position of a point. Instead of using \( x \) and \( y \) like in Cartesian coordinates, polar coordinates use the distance from a reference point and an angle from a reference direction.For an ellipse in a polar coordinate system:
In our exercise, we express the orbit of a planet as \( r = a(1 - e\cos \theta) / (1 - e^2) \) using polar coordinates.
- The pole is often considered one of the foci of the ellipse, particularly when modeling orbits.
- \( r \) represents the radial distance from the pole to a point on the ellipse.
- \( \theta \) is the angle formed with a reference direction, typically the positive x-axis.
In our exercise, we express the orbit of a planet as \( r = a(1 - e\cos \theta) / (1 - e^2) \) using polar coordinates.
Orbital Motion
Orbital motion refers to the path an object, such as a planet, takes as it moves around another object, such as a star. Most orbital paths are ellipses, with the more massive body located at one of the foci of the ellipse.
Orbits are governed by gravitational forces, described by Kepler's laws of planetary motion, which explain how planets and other celestial objects move through space. Key factors in orbital motion include:
This knowledge is crucial for predicting not just the movement of planets but also of satellites and other objects in space.
Orbits are governed by gravitational forces, described by Kepler's laws of planetary motion, which explain how planets and other celestial objects move through space. Key factors in orbital motion include:
- The shape of the orbit, usually elliptical, which depends on eccentricity.
- The speed of the object in orbit, which changes as it moves closer or farther from the central body.
- The position of the object in its orbit, which can be defined using polar coordinates.
This knowledge is crucial for predicting not just the movement of planets but also of satellites and other objects in space.
Other exercises in this chapter
Problem 54
Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. $$x^{2}+y^{2}-4 x-6 y-23=0$$
View solution Problem 54
Find an equation of the ellipse with vertices (0,±8) and eccentricity \(e=\frac{1}{2}.\)
View solution Problem 55
A point in rectangular coordinates is given. Convert the point to polar coordinates. $$(\sqrt{3},-1)$$
View solution Problem 55
Use a graphing utility to graph the polar equation. Describe your viewing window. $$r=3(2-\sin \theta)$$
View solution