Problem 55
Question
The enthalpy and entropy change for a chemical reaction are \(-2.5 \times 10^{3} \mathrm{~J} \mathrm{~mol}^{-1}\) and \(7.4 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) respec- tively. The reaction at \(298 \mathrm{~K}\). is (a) non-spontaneous (b) spontaneous (c) reversible (d) irreversible
Step-by-Step Solution
Verified Answer
The reaction is spontaneous (b) because \( \Delta G < 0 \).
1Step 1: Understand the Gibbs Free Energy Equation
The spontaneity of a reaction is determined by its Gibbs free energy change (\( \Delta G \)). The equation to calculate Gibbs free energy is:\[ \Delta G = \Delta H - T \Delta S \]where \( \Delta G \) is the change in Gibbs free energy, \( \Delta H \) is the change in enthalpy, \( T \) is the temperature in Kelvin, and \( \Delta S \) is the change in entropy.
2Step 2: Substitute Given Values Into the Equation
We know \( \Delta H = -2.5 \times 10^3 \text{ J mol}^{-1} \), \( \Delta S = 7.4 \text{ JK}^{-1} \text{ mol}^{-1} \), and \( T = 298 \text{ K} \). Substitute these values into the Gibbs free energy equation:\[ \Delta G = (-2500) - (298)(7.4) \]
3Step 3: Calculate the Temperature Term
First, calculate the product of temperature and entropy change:\[ 298 \times 7.4 = 2205.2 \text{ J mol}^{-1} \]
4Step 4: Solve for Gibbs Free Energy
Subtract the temperature-entropy product from the enthalpy change:\[ \Delta G = -2500 - 2205.2 \]\[ \Delta G = -4705.2 \text{ J mol}^{-1} \]
5Step 5: Analyze Gibbs Free Energy Result
A reaction is spontaneous when \( \Delta G < 0 \). Here, \( \Delta G = -4705.2 \text{ J mol}^{-1} \), which means the reaction is spontaneous since the value is negative.
Key Concepts
Enthalpy ChangeEntropy ChangeSpontaneous ReactionChemical Thermodynamics
Enthalpy Change
Enthalpy change, denoted as \( \Delta H \), represents the heat absorbed or released in a reaction under constant pressure conditions. It indicates whether a reaction is endothermic (absorbing heat) or exothermic (releasing heat). In our example, \( \Delta H = -2.5 \times 10^3 \text{ J mol}^{-1} \), which means the reaction releases heat, making it exothermic.
- Positive \( \Delta H\) implies absorbing heat (endothermic).
- Negative \( \Delta H\) implies releasing heat (exothermic).
Entropy Change
Entropy change, represented as \( \Delta S \), describes the degree of disorder or randomness in a system. A higher value of \( \Delta S \) indicates more disorder. In chemical reactions, entropy changes help to determine the spontaneity along with temperature effects.The given problem has \( \Delta S = 7.4 \text{ JK}^{-1} \text{ mol}^{-1} \), suggesting a slight increase in disorder within the system during the reaction.
- Positive \( \Delta S \) suggests increasing disorder.
- Negative \( \Delta S \) implies a decrease in disorder.
Spontaneous Reaction
A reaction is termed spontaneous if it proceeds on its own without external energy input. It’s driven by favorable conditions of enthalpy and entropy at a given temperature.To determine spontaneity, the Gibbs free energy change \( \Delta G \) is used. The criteria are:
- If \( \Delta G < 0 \), the reaction is spontaneous.
- If \( \Delta G > 0 \), the reaction is non-spontaneous.
- If \( \Delta G = 0 \), the reaction is at equilibrium (neither spontaneous nor non-spontaneous).
Chemical Thermodynamics
Chemical thermodynamics is the branch of chemistry that studies the energy changes, particularly in the form of heat, during chemical reactions. It provides the tools to evaluate if a process is feasible and predict the direction of chemical reactions.Key aspects in chemical thermodynamics include:
- Enthalpy (\( \Delta H \)) - reflects heat exchange.
- Entropy (\( \Delta S\)) - reflects disorder or randomness.
- Gibbs Free Energy (\( \Delta G\)) - determines spontaneity.
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