Problem 55
Question
$$\text { Prove the identity.}$$ $$\cos (\pi-x)=-\cos x$$
Step-by-Step Solution
Verified Answer
Question: Prove the trigonometric identity \(\cos (\pi-x)=-\cos x\) using a geometric approach.
Answer: By analyzing the positions of angles x and \((\pi-x)\) on the unit circle, we find that the x-coordinate of the terminal point for the angle \((\pi-x)\) is the negative of the x-coordinate for the angle x, since they are in opposite quadrants. This demonstrates that the cosine values are related by a negative sign, proving the trigonometric identity \(\cos (\pi-x)=-\cos x\).
1Step 1: Identify the given trigonometric identity
We are given the identity to prove: $$\cos (\pi-x)=-\cos x$$
2Step 2: Recall the definition of cosine in the unit circle
In the unit circle, the cosine of an angle is the x-coordinate of the point where the terminal side of the angle intersects the circle. For example, if we have an angle \(x\) in radians, we can find its terminal point (x, y) and the cosine function is given by the x-coordinate of that point: \(\cos(x) = x.\)
3Step 3: Visualize the angles x and \((\pi-x)\) on the unit circle
Consider x to be a positive angle in the first or second quadrant. Then, \(\pi-x\) can be seen as the angle formed by rotating π radians counterclockwise (or x radians clockwise) from the terminal side of x. This will result in the corresponding terminal side being in the third or fourth quadrant.
4Step 4: Determine the cosine values of both angles
Since the angle \((\pi-x)\) is in the third or fourth quadrant, its cosine value will be negative (recall that cosine values are negative for angles in the second and third quadrants). Meanwhile, the angle x is in the first or second quadrant, meaning its cosine value will be positive.
5Step 5: Prove the equality
Now we can see that the x-coordinate of the terminal point for the angle \((\pi-x)\) is the negative of the x-coordinate for the angle x, since they are in opposite quadrants. Therefore, the two cosine values are related by a negative sign, which proves the given identity: $$\cos (\pi-x)=-\cos x$$
Key Concepts
Unit CircleCosine FunctionAngle Quadrants
Unit Circle
The unit circle is a fundamental concept in trigonometry that aids in understanding the relationships between angles and trigonometric functions. This circle has a radius of 1 and is centered at the origin of a coordinate system.
Here are some essential aspects of the unit circle:
Here are some essential aspects of the unit circle:
- Every point on the unit circle has coordinates that are determined by the angle \( heta \) measured from the positive x-axis.
- The x-coordinate of a point on the circle is equal to \( \cos(\theta) \) and the y-coordinate is equal to \( \sin(\theta) \).
- Since the radius is 1, the equation of the unit circle is \( x^2 + y^2 = 1 \).
- The unit circle helps to visualize trigonometric functions and understand their periodic nature as you rotate around the circle.
Cosine Function
The cosine function is a fundamental trigonometric function that forms the backbone of many mathematical applications.
Let's dive deeper into some key properties of the cosine function:
Let's dive deeper into some key properties of the cosine function:
- The cosine function relates an angle to the x-coordinate on the unit circle. For any angle \( \theta \), \( \cos(\theta) \) is the value of the x-coordinate where the terminal side of the angle (radius) intersects the unit circle.
- Cosine is a periodic function with a period of \( 2\pi \). This means that after every \( 2\pi \) radians, the value of \( \cos(\theta) \) repeats.
- The cosine function has even symmetry, which implies that \( \cos(\theta) = \cos(-\theta) \).
- Values of \( \cos(\theta) \) range from -1 to 1 for angles between 0 and \( \pi \).
Angle Quadrants
The coordinate plane is divided into four quadrants, and each quadrant has distinct characteristics that affect the sign and value of trigonometric functions, such as cosine.
Here's a brief overview of angle quadrants:
Here's a brief overview of angle quadrants:
- Quadrant I: Angles range from \( 0 \) to \( \frac{\pi}{2} \) radians. Here, both sine and cosine values are positive.
- Quadrant II: Angles range from \( \frac{\pi}{2} \) to \( \pi \) radians. The sine is positive while the cosine is negative.
- Quadrant III: Angles range from \( \pi \) to \( \frac{3\pi}{2} \) radians. Both sine and cosine values are negative.
- Quadrant IV: Angles range from \( \frac{3\pi}{2} \) to \( 2\pi \). Here, sine is negative, and cosine is positive.
Other exercises in this chapter
Problem 55
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State whether or not the equation is an identity. If it is an identity, prove it. $$\frac{\sec ^{2} x-1}{\sec ^{2} x}=\sin ^{2} x$$
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Simplify the given expression. $$\cos ^{2}\left(\frac{x}{2}\right)-\sin ^{2}\left(\frac{x}{2}\right)$$
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