Problem 55
Question
Solve each compound inequality using the compact form. Express the solution sets in interval notation. \(-3<2-x<3\)
Step-by-Step Solution
Verified Answer
The solution is \((-1, 5)\).
1Step 1: Understand the Inequality
We have a compound inequality: \(-3 < 2 - x < 3\). This means we need to find the values of \(x\) that make both inequalities true: 1. \(-3 < 2 - x\) 2. \(2 - x < 3\).
2Step 2: Solve the First Inequality
Focus on the inequality \(-3 < 2 - x\):1. Subtract 2 from both sides to isolate \(-x\): \(-3 - 2 < -x\) simplifies to \(-5 < -x\).2. Multiply both sides by \(-1\) (and remember to flip the inequality sign):\(5 > x\).
3Step 3: Solve the Second Inequality
Focus on the inequality \(2 - x < 3\):1. Subtract 2 from both sides to isolate \(-x\):\(2 - 2 - x < 3 - 2\) simplifies to \(-x < 1\).2. Multiply both sides by \(-1\) (and remember to flip the inequality sign):\(x > -1\).
4Step 4: Combine the Solutions
We now combine the two results from the inequalities:1. From Step 2, the solution is \(x < 5\).2. From Step 3, the solution is \(x > -1\).3. Combine: \(-1 < x < 5\).
5Step 5: Express in Interval Notation
Now express the combined solution \(-1 < x < 5\) in interval notation. This corresponds to the open interval: \((-1, 5)\).
Key Concepts
Interval NotationSolving InequalitiesAlgebraic Solution Steps
Interval Notation
Interval notation is a way to describe subsets of real numbers on a number line. Instead of writing inequalities, you can succinctly express the range of values in a more compact form. For instance, the interval \((-1, 5)\) describes all numbers between -1 and 5, excluding -1 and 5 themselves. This is known as an open interval because it does not include its endpoints.
In interval notation:
In interval notation:
- Round brackets \( ( ) \) represent open intervals, which do not include endpoints.
- Square brackets \( [ ] \) indicate closed intervals, including endpoints.
- Mixing brackets \( ( ] \) or \( [ ) \) allows for one-sided inclusion, like \( (a, b] \) which includes b but not a.
Solving Inequalities
Inequalities express the relationship between two values, indicating if one value is larger or smaller than the other. Solving inequalities involves finding the set of all possible values that an unknown variable can take to make the inequality true.
In a compound inequality such as \(-3 < 2-x < 3\), you need to solve two inequalities at once:
In a compound inequality such as \(-3 < 2-x < 3\), you need to solve two inequalities at once:
- The first inequality is \(-3 < 2-x\).
- The second inequality is \(2-x < 3\).
- Isolate the variable on one side.
- Use inverse operations like addition, subtraction, multiplication, or division.
- Remember that multiplying or dividing by a negative number flips the inequality sign.
Algebraic Solution Steps
When faced with a compound inequality, the algebraic solution involves breaking down the problem into manageable parts. Each step focuses on isolating the variable to determine the values that satisfy the inequality.
For the compound inequality \(-3 < 2 - x < 3\), follow these algebraic solution steps:
For the compound inequality \(-3 < 2 - x < 3\), follow these algebraic solution steps:
- Step 1: Solve the first inequality \(-3 < 2 - x\). Subtract 2 from both sides to simplify to \(-5 < -x\). Then, multiply by -1 to get \(5 > x\).
- Step 2: Solve the second inequality \(2 - x < 3\). Again, subtract 2 from both sides to get \(-x < 1\). Multiply by -1, flipping the inequality, so \(x > -1\).
- Step 3: Combine the solutions from both steps: \(-1 < x < 5\). This shows the range where the variable x satisfies both inequalities.
Other exercises in this chapter
Problem 54
Use an algebraic approach to solve each problem. Find four consecutive integers whose sum is \(-118\).
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For Problems \(55-64\), solve each equation and inequality by inspection. \(|2 x+1|=-4\)
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Solve each inequality and express the solution set using interval notation. \(5(x-4)-6(x+2)
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Solve each of Problems \(47-62\) by setting up. Juan starts walking at 4 miles per hour. An hour and a half later, Cathy starts jogging along the same route at
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