Problem 55
Question
Solve each compound inequality. $$-11<2 x-1 \leq-5$$
Step-by-Step Solution
Verified Answer
The solution to the compound inequality is \(-5 < x \leq -2\).
1Step 1: Split the Compound Inequality
Divide the compound inequality into two separate ones: i. \(-11 < 2x - 1\) and ii. \(2x - 1 \leq -5\)
2Step 2: Solve the first inequality
For the first inequality \(-11 < 2x - 1\), add 1 to both sides to isolate \(2x\), leading to \(-10 < 2x\). Then, divide both sides by 2 to solve for \(x\), so \(x > -5\).
3Step 3: Solve the second inequality
For the second inequality \(2x - 1 \leq -5\), add 1 to both sides to isolate \(2x\), leading to \(2x \leq -4\). Then, divide both sides by 2 to solve for \(x\), so \(x \leq -2\).
4Step 4: Combine Solutions
Now, combine the solutions of the two inequalities to find the intersection. The previous two steps gave us \(x > -5\) and \(x \leq -2\), both hold true for the solution which is \(-5 < x \leq -2\)
Other exercises in this chapter
Problem 55
Complex numbers are used in electronics to describe the current in an electric circuit. Ohm's law relates the current in a circuit, \(I\), in amperes, the volta
View solution Problem 55
Solve each equation in Exercises \(47-64\) by completing the square. $$ x^{2}-5 x+6=0 $$
View solution Problem 55
By making an appropriate substitution. $$(x-5)^{2}-4(x-5)-21=0$$
View solution Problem 55
Find all values of \(x\) satisfying the given conditions. \(y_{1}=\frac{5}{x+4}, y_{2}=\frac{3}{x+3}, y_{3}=\frac{12 x+19}{x^{2}+7 x+12},\) and \(y_{1}+y_{2}=y_
View solution