Problem 55
Question
Simplify each exponential expression $$ \left(4 x^{3}\right)^{-2} $$
Step-by-Step Solution
Verified Answer
The simplified form of the given expression is \( \frac{1}{16x^{6}} \).
1Step 1: Rules of negative exponents
First, it's useful to understand the rules that govern negative exponents. Generally, if \( a \) is any non-zero real number and \( n \) is any integer, then \( a^{-n} = \frac{1}{a^{n}} \). So, \( (4x^3)^{-2} \) becomes \( \frac{1}{{(4x^3)}^{2}} \)
2Step 2: Apply the rules of exponents
Applying the rule of exponents \( \left(a^m\right)^n = a^{mn} \), we can simplify \( \frac{1}{{(4x^3)}^{2}} \) to \( \frac{1}{4^{2} \cdot (x^{3})^{2}} \). This further simplifies to \( \frac{1}{16x^{6}} \)
Key Concepts
Negative ExponentsRules of ExponentsSimplifying Expressions
Negative Exponents
When dealing with negative exponents, it's important to understand what they signify. A negative exponent indicates that the base should be moved from one part of a fraction to the other. More simply, a negative exponent represents the reciprocal of the base raised to the positive version of that exponent. For example:
- If you have an exponential expression like \( a^{-n} \), it is equivalent to \( \frac{1}{a^n} \).
- This means that \( a^{-n} \) "flips" the base \( a \) to the denominator of a fraction and makes the exponent positive.
Rules of Exponents
The rules of exponents are vital for efficiently simplifying expressions involving powers. Here are some key rules:
- Product of Powers: \( a^m \times a^n = a^{m+n} \)
- Power of a Power: \( (a^m)^n = a^{m \times n} \)
- Quotient of Powers: \( \frac{a^m}{a^n} = a^{m-n} \)
Simplifying Expressions
Simplifying expressions is the process of reducing complexity while keeping the expression equivalent. In algebra, this often involves combining like terms, applying rules, or simplifying fractions and powers.
- Initially, we had \( (4x^3)^{-2} \), which we rewritten using the negative exponent rule into \( \frac{1}{(4x^3)^2} \).
- Next, using the rules of exponents, we broke it down to \( \frac{1}{4^2 \cdot (x^3)^2} \).
- By calculating the powers individually, it becomes \( \frac{1}{16x^6} \).
Other exercises in this chapter
Problem 54
Add or subtract as indicated. $$ \frac{6 x^{2}+17 x-40}{x^{2}+x-20}+\frac{3}{x-4}-\frac{5 x}{x+5} $$
View solution Problem 55
state the name of the property illustrated. $$ 2(-8+6)=-16+12 $$
View solution Problem 55
Find each product. $$$$(x-3)^{3}$$
View solution Problem 55
Evaluate each expression in Exercises \(49-60\), or indicate that the root is not a real number. $$\sqrt[4]{(-3)^{4}}$$
View solution