Problem 55
Question
Rationalize each denominator. $$ \sqrt{\frac{2}{7}} $$
Step-by-Step Solution
Verified Answer
The rationalized form is \( \frac{\sqrt{14}}{7} \).
1Step 1: Identify the fraction under the square root
We start by recognizing that the expression inside the square root, \( \frac{2}{7} \), is a fraction with a numerator of 2 and a denominator of 7.
2Step 2: Apply the square root identity for fractions
We can simplify \( \sqrt{\frac{2}{7}} \) by using the identity \( \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \). Applying this identity, the expression becomes \( \frac{\sqrt{2}}{\sqrt{7}} \).
3Step 3: Rationalize the denominator
To remove the square root from the denominator, multiply both the numerator and the denominator by \( \sqrt{7} \). This gives us \( \frac{\sqrt{2} \cdot \sqrt{7}}{\sqrt{7} \cdot \sqrt{7}} \), which simplifies to \( \frac{\sqrt{14}}{7} \) since \( \sqrt{7} \cdot \sqrt{7} = 7 \).
Key Concepts
Square Root PropertiesFractions in RadicalsMultiplication of Radicals
Square Root Properties
When dealing with square roots, it's important to understand their fundamental properties. One of the key concepts is that the square root of a number represents a value that, when multiplied by itself, gives the original number. For example, \( \sqrt{4} = 2 \) because \( 2 \times 2 = 4 \).
Square roots have a specific set of rules that make them easier to manipulate:
Understanding these rules is crucial when rationalizing denominators, as they help you manipulate square roots in a systematic way.
Square roots have a specific set of rules that make them easier to manipulate:
- Product Property of Square Roots: \( \sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b} \)
- Quotient Property of Square Roots: \( \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \)
Understanding these rules is crucial when rationalizing denominators, as they help you manipulate square roots in a systematic way.
Fractions in Radicals
Fractions can be present either under a square root, as in \( \sqrt{\frac{a}{b}} \), or as the result of a division involving square roots, such as \( \frac{\sqrt{a}}{b} \). When dealing with these types of expressions, the properties of square roots are often applied to simplify them.
The step of splitting the square root of a fraction into the quotient of square roots is particularly useful. For example:
The step of splitting the square root of a fraction into the quotient of square roots is particularly useful. For example:
- \( \sqrt{\frac{2}{7}} \) becomes \( \frac{\sqrt{2}}{\sqrt{7}} \)
- This step allows you to work with each number separately, which can simplify further calculations.
Multiplication of Radicals
Understanding how to multiply radicals is essential when simplifying expressions, particularly when rationalizing denominators. Radicals can be multiplied using the product property of square roots, which states that \( \sqrt{a} \times \sqrt{b} = \sqrt{a \cdot b} \).
In the context of rationalizing denominators, this property allows you to effectively eliminate square roots from the denominator. Here's how it works:
In the context of rationalizing denominators, this property allows you to effectively eliminate square roots from the denominator. Here's how it works:
- Given the expression \( \frac{\sqrt{2}}{\sqrt{7}} \), multiply both the numerator and denominator by \( \sqrt{7} \) to maintain the expression's equality.
- This results in \( \frac{\sqrt{2} \times \sqrt{7}}{\sqrt{7} \times \sqrt{7}} \), or \( \frac{\sqrt{14}}{7} \).
- The product \( \sqrt{7} \times \sqrt{7} = 7 \) simplifies the denominator to an integer.
Other exercises in this chapter
Problem 54
Solve each equation. $$ \left(a^{2}+2 a\right)^{1 / 3}=2(a-1)^{1 / 3} $$
View solution Problem 55
Simplify each expression. All variables represent positive real numbers. See Example 4. $$ -\left(\frac{x^{5}}{32}\right)^{4 / 5} $$
View solution Problem 55
Find the midpoint of the line segment with the given endpoints. \((0,0),(6,8)\)
View solution Problem 55
Find the domain of each function. See Example 4. $$ f(x)=\sqrt{x+6} $$
View solution