Problem 55
Question
Matrix Multiplication Use matrix multiplication to determine whether each matrix is a solution of the system of equations. Use a graphing utility to verify your results. \(\left\\{\begin{aligned} x+2 y &=4 \\ 3 x+2 y &=0 \end{aligned}\right.\) (a) \(\left[\begin{array}{l}2 \\ 1\end{array}\right]\) (b) \(\left[\begin{array}{r}-2 \\ 3\end{array}\right]\) (c) \(\left[\begin{array}{r}-4 \\ 4\end{array}\right]\) (d) \(\left[\begin{array}{r}2 \\ -3\end{array}\right]\)
Step-by-Step Solution
Verified Answer
The only solution to the system of equations is matrix (b) \(\left[\begin{array}{r}-2 \ 3\end{array}\right]\). The other matrices (a, c, and d) are not solutions to the system.
1Step 1: Matrix (a)
Substitute \(x = 2\) and \(y = 1\) into the system of equations. The system becomes: \(2 + 2*1 = 4\) and \(3*2 + 2*1 = 0\). The first equation holds as \(4 = 4\), however the second equation does not as \(8 != 0\). Therefore, matrix (a) is not a solution.
2Step 2: Matrix (b)
Substitute \(x = -2\) and \(y = 3\) into the system of equations. The system becomes: \(-2 + 2*3 = 4\) and \(3*(-2) + 2*3 = 0\). Both equations hold as they satisfy their respective sides, thus Matrix (b) is a solution.
3Step 3: Matrix (c)
Substitute \(x = -4\) and \(y = 4\) into the system of equations. The system becomes: \(-4 + 2*4 = 4\) and \(3*(-4) + 2*4 = 0\). The first equation holds as \(4 = 4\), however, the second equation does not as \(-4 != 0\). Therefore, matrix (c) is not a solution.
4Step 4: Matrix (d)
Substitute \(x = 2\) and \(y = -3\) into the system of equations. The system becomes: \(2 + 2*(-3) = 4\) and \(3*2 + 2*(-3) = 0\). Neither equations hold as they do not satisfy their respective sides. Therefore, matrix (d) is not a solution.
Key Concepts
Understanding System of EquationsSolution Verification in SystemsUsing a Graphing UtilityExploring the Substitution Method
Understanding System of Equations
A **system of equations** consists of two or more equations that share variables, and the goal is to find the values that satisfy all given equations simultaneously. In the given exercise, the system is made up of two linear equations: \[ \begin{aligned} x + 2y &= 4, \ 3x + 2y &= 0 \end{aligned} \] These equations share variables \(x\) and \(y\). Solving a system of equations involves finding pairs \((x, y)\) that make both equations true. Key methods to solve systems include:
- Graphical approach, where each equation is drawn on a graph and intersections represent solutions.
- Substitution method, focusing on solving one equation for one variable and replacing it in the other.
- Matrix multiplication, as used in this example, to determine if given matrices are solutions.
Solution Verification in Systems
**Solution verification** is critical after finding potential solutions to confirm that they truly satisfy the entire system of equations. This process ensures accuracy and serves to eliminate mistakes. Here, the potential solutions are represented by matrices where the elements suggest specific \(x\) and \(y\) values. Two key steps to verify solutions include:
- Substitute the potential \(x\) and \(y\) values into each equation of the system.
- Check if both sides of the equations are equal, ensuring each equation holds true.
Using a Graphing Utility
A **graphing utility** is a digital tool designed to plot equations and visually analyze solutions of systems. This helps in double-checking solutions derived through algebraic methods.
Steps for using a graphing utility:
- Input each equation from the system and display their graphs.
- Observe the points where the lines intersect, representing the solution(s).
- Cross-verify these points with solutions found through other methods.
Exploring the Substitution Method
The **substitution method** is an effective tool for solving systems of equations, particularly when working with linear systems.Here’s how it typically works:
- Select one of the equations and solve for one of the variables in terms of the other. For example, from \(x + 2y = 4\), solve for \(x\) to get \(x = 4 - 2y\).
- Substitute this value into the other equation. Replace \(x\) in the second equation \(3x + 2y = 0\) with \(4 - 2y\): \ 3(4 - 2y) + 2y = 0
- Solve for the remaining variable \(y\). Plug this back into the first equation to solve for \(x\).
Other exercises in this chapter
Problem 55
Use a graphing utility to graph the two equations. Use the graphs to approximate the solution of the system. Round your results to three decimal places. $$\left
View solution Problem 55
Use a graphing utility to approximate all points of intersection of the graphs of equations in the system. Round your results to three decimal places. Verify yo
View solution Problem 56
An augmented matrix that represents a system of linear equations (in the variables \(x\) and \(y\) or \(x, y,\) and \(z\) ) has been reduced using Gauss-Jordan
View solution Problem 56
Solve for \(x\) $$\left|\begin{array}{cc} x+1 & 2 \\ -1 & x \end{array}\right|=4$$
View solution