Problem 55
Question
Is the function given by $$ G(x)=\left\\{\begin{array}{ll} \frac{1}{2} x+1, & \text { for } x<4 \\ -x+5, & \text { for } x>4 \end{array}\right. $$ continuous at \(x=4\) ? Why or why not?
Step-by-Step Solution
Verified Answer
The function \(G(x)\) is not continuous at \(x=4\) because the left and right-hand limits differ.
1Step 1: Definition of Continuity
A function is continuous at a point if the left-hand limit at that point equals the right-hand limit and both equal the function's value at that point. We must check these conditions for \(G(x)\) at \(x=4\).
2Step 2: Calculate Left-Hand Limit at x=4
For \(x<4\), the function is given by \(\frac{1}{2}x + 1\). We calculate the left-hand limit as\[\lim_{{x \to 4^-}} G(x) = \lim_{{x \to 4^-}} \left(\frac{1}{2}x + 1\right).\]Substituting \(x = 4\), we get \[\lim_{{x \to 4^-}} G(x) = \frac{1}{2}(4) + 1 = 2 + 1 = 3.\]
3Step 3: Calculate Right-Hand Limit at x=4
For \(x>4\), the function is given by \(-x + 5\). We calculate the right-hand limit as\[\lim_{{x \to 4^+}} G(x) = \lim_{{x \to 4^+}} (-x + 5).\]Substituting \(x = 4\), we get \[\lim_{{x \to 4^+}} G(x) = -4 + 5 = 1.\]
4Step 4: Compare Limits and Function Value at x=4
Since \(x=4\) is not included in either domain piece, we do not have a function value at \(x=4\) in the piecewise definition.Contrast the left-hand limit, \(3\), and the right-hand limit, \(1\). They do not match, indicating that the limit of the function at \(x=4\) does not exist.
5Step 5: Conclusion on Continuity
Since the left-hand and right-hand limits are not equal, \(G(x)\) is not continuous at \(x=4\).
Key Concepts
Piecewise FunctionsLimits and ContinuityEvaluating Limits
Piecewise Functions
Piecewise functions are unique in that their equations change based on the input value, or more specifically, the range of input values. This means that the function behaves differently in separate intervals of the domain, which can make analyzing them a bit challenging. Consider the function from our exercise:
- For values of "x" less than 4, the function is described by \( \frac{1}{2}x + 1 \).
- For "x" greater than 4, the function is given by \( -x + 5 \).
Limits and Continuity
In calculus, understanding limits and continuity is crucial when dealing with piecewise functions. A function is continuous at a certain point if the following three conditions are satisfied:
Continuous functions appear as unbroken lines on a graph; imagine a continuous path without lifting your pencil from paper. However, if any of the three conditions for continuity fails, as with our example function, it suggests a break or a gap, showing discontinuity at that point.
- The function is defined at the specific point.
- The limit of the function exists at that point.
- The limit at that point equals the function's value.
Continuous functions appear as unbroken lines on a graph; imagine a continuous path without lifting your pencil from paper. However, if any of the three conditions for continuity fails, as with our example function, it suggests a break or a gap, showing discontinuity at that point.
Evaluating Limits
Evaluating limits is a fundamental skill in calculus, especially when assessing a function's continuity. To determine the continuity at a specific point like "x = 4" in our piecewise function, we must compute the limits from both sides:
Since the left-hand and right-hand limits differ, this results in a non-existing overall limit at "x = 4." When these limits do not equal each other, it acts as a clear indicator that the function is not continuous at that point. Understanding how to calculate and compare these directional limits is crucial as it reveals function behavior near transition points, crucial for grasping broader calculus concepts.
- **Left-Hand Limit**: Calculated for \( x<4 \), using \( \frac{1}{2}x + 1 \). As "x" approaches 4, this limit is 3.
- **Right-Hand Limit**: Evaluated for \( x>4 \), with \( -x + 5 \). As "x" approaches 4 again, this limit stands at 1.
Since the left-hand and right-hand limits differ, this results in a non-existing overall limit at "x = 4." When these limits do not equal each other, it acts as a clear indicator that the function is not continuous at that point. Understanding how to calculate and compare these directional limits is crucial as it reveals function behavior near transition points, crucial for grasping broader calculus concepts.
Other exercises in this chapter
Problem 55
Preston's Leatherworks find that the revenue, in dollars, from the sale of \(x\) belts is given by \(R(x)=45 x^{9 / 10}\). Find the rate at which average revenu
View solution Problem 55
Find \(\frac{d y}{d t} \text { if } y=\frac{1}{u^{2}+u}\) and \(u=5+3 t\)
View solution Problem 56
Find \(y^{\prime}\) $$ \text { If } y=\frac{1}{3 x^{4}}, \text { find }\left.\frac{d y}{d x}\right|_{x=-1} $$
View solution Problem 56
Let \(G\) be a function given by $$G(x)=\left\\{\begin{array}{ll}x^{3}, & \text { for } x \leq 1 \\ 3 x-2, & \text { for } x>1\end{array}\right.$$ a) Verify tha
View solution