Problem 55
Question
In the Dumas-bulb technique for determining the molar mass of an unknown liquid, you vaporize the sample of a liquid that boils below \(100^{\circ} \mathrm{C}\) in a boiling-water bath and determine the mass of vapor required to fill the bulb (see drawing, next page). From the following data, calculate the molar mass of the unknown liquid: mass of unknown vapor, \(1.012 \mathrm{~g}\); volume of bulb, \(354 \mathrm{~cm}^{3} ;\) pressure, 742 torr; temperature, \(99^{\circ} \mathrm{C}\).
Step-by-Step Solution
Verified Answer
The molar mass of the unknown liquid is approximately \(28.4~\text{g/mol}\), which is calculated using the ideal gas law, converting units, and finding the number of moles before dividing the mass of the vapor by the moles.
1Step 1: Convert the given data to appropriate units
Before we use the ideal gas law formula, we need to make sure the given values are in the correct units. The pressure should be in atmospheres, the volume should be in liters, and the temperature should be in Kelvin.
Given values:
- Mass of unknown vapor, \(m = 1.012~\text{g}\)
- Volume of bulb, \(V = 354~\text{cm}^3\)
- Pressure, \(P = 742~\text{torr}\)
- Temperature, \(T = 99^\circ \text{C}\)
Converting the units, we get:
- Volume in liters: \(V = 354~\text{cm}^3 \times \frac{1~\text{L}}{1000~\text{cm}^3} = 0.354~\text{L}\)
- Pressure in atmospheres: \(P = 742~\text{torr} \times \frac{1~\text{atm}}{760~\text{torr}} = 0.9763~\text{atm}\)
- Temperature in Kelvin: \(T = 99^\circ \text{C} + 273.15 = 372.15~\text{K}\)
2Step 2: Use the ideal gas law to find the number of moles
Now that we have the necessary values in the appropriate units, we can use the ideal gas law formula, which is:
\(PV = nRT\)
Where:
- P is the pressure in atmospheres.
- V is the volume in liters.
- n is the number of moles of gas.
- R is the ideal gas constant (\(0.0821~\text{L·atm/mol·K}\))
- T is the temperature in Kelvin.
We need to find the value of n, so we can rewrite the formula as:
\(n = \frac{PV}{RT}\)
Substituting the given values, we get:
\(n = \frac{(0.9763~\text{atm})(0.354~\text{L})}{(0.0821~\text{L·atm/mol·K})(372.15~\text{K})} \approx 0.0356~\text{mol}\)
3Step 3: Calculate the molar mass of the unknown liquid
We now have the number of moles of the vapor (n) and the mass of the vapor (m). We can use this information to calculate the molar mass (M) of the unknown liquid using the formula:
\(M = \frac{\text{mass}}{\text{moles}}\)
Using the given mass and the calculated moles, we get:
\(M = \frac{1.012~\text{g}}{0.0356~\text{mol}} \approx 28.4~\text{g/mol}\)
The molar mass of the unknown liquid is approximately \(28.4~\text{g/mol}\).
Key Concepts
Dumas-bulb techniqueIdeal gas lawUnit conversion
Dumas-bulb technique
The Dumas-bulb technique is a classic laboratory method for determining the molar mass of a volatile liquid. The process involves vaporizing a known mass of a liquid in a flask called a Dumas bulb, which is then heated to boil off the liquid. As the liquid vaporizes, it displaces air inside the bulb until only the vapor of the liquid remains. Once the vapor has filled the bulb, it exerts a pressure equal to the atmospheric pressure, if the bulb is open to the atmosphere, or a known pressure otherwise.
A key point in this process is that all air must be expelled from the bulb to ensure that the pressure measured is solely due to the vapor of the liquid. Assume ideal behavior of the gas, the parameters such as the volume of the bulb, the pressure of the vapor, and the temperature of the surrounding environment are used to determine the amount of gas present. Since the mass of the vapor is known, this allows for direct calculation of the molar mass. It's essential to take the measurements when the vapor is in equilibrium with its liquid to prevent the loss of material and obtain accurate results.
A key point in this process is that all air must be expelled from the bulb to ensure that the pressure measured is solely due to the vapor of the liquid. Assume ideal behavior of the gas, the parameters such as the volume of the bulb, the pressure of the vapor, and the temperature of the surrounding environment are used to determine the amount of gas present. Since the mass of the vapor is known, this allows for direct calculation of the molar mass. It's essential to take the measurements when the vapor is in equilibrium with its liquid to prevent the loss of material and obtain accurate results.
Ideal gas law
The ideal gas law is a fundamental equation in chemistry that relates the pressure, volume, temperature, and number of moles of an ideal gas. Expressed as PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin. Ideal gases are hypothetical gases whose molecules occupy negligible space and have no intermolecular forces.
Because real gases exhibit non-ideal behavior, the ideal gas law is most accurate under conditions of low pressure and high temperature. In the exercise solution, the ideal gas law helps calculate the number of moles of vapor present. With the assumption that the vapor behaves as an ideal gas, the mass and the volume of the gas allows for a straightforward determination of its molar mass. To apply the ideal gas law effectively, remember that all units must be consistent, which is why unit conversion is a critical step before solving.
Because real gases exhibit non-ideal behavior, the ideal gas law is most accurate under conditions of low pressure and high temperature. In the exercise solution, the ideal gas law helps calculate the number of moles of vapor present. With the assumption that the vapor behaves as an ideal gas, the mass and the volume of the gas allows for a straightforward determination of its molar mass. To apply the ideal gas law effectively, remember that all units must be consistent, which is why unit conversion is a critical step before solving.
Unit conversion
Unit conversion is crucial in scientific calculations to ensure that equations are dimensionally consistent and that quantities are accurately compared. In chemistry, particularly in gas laws, it is common to work with standard units of liters for volume, Kelvin for temperature, and atmospheres for pressure. If measurements are taken in other units, they must be converted before using them in formulas.
For example, as done in the exercise, volume is converted from cubic centimeters to liters (1 L = 1000 cm3), pressure is converted from torr to atmospheres (1 atm = 760 torr), and temperature is converted from Celsius to Kelvin (K = °C + 273.15). Remember that incorrect or inconsistent units can lead to substantial errors in the final result. Always be meticulous with unit conversion to ensure the integrity of your calculations.
For example, as done in the exercise, volume is converted from cubic centimeters to liters (1 L = 1000 cm3), pressure is converted from torr to atmospheres (1 atm = 760 torr), and temperature is converted from Celsius to Kelvin (K = °C + 273.15). Remember that incorrect or inconsistent units can lead to substantial errors in the final result. Always be meticulous with unit conversion to ensure the integrity of your calculations.
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