Problem 55
Question
In Problems \(51-56\), use the laws of logarithms in Theorem \(6.2 .1\) to rewrite the given expression as one logarithm. $$ \ln 5+\ln 5^{2}+\ln 5^{3}-\ln 5^{6} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to 0.
1Step 1: Apply the Power Rule for Logarithms
According to the power rule: \( \ln(a^b) = b\ln(a) \). We will apply this rule to each term in the expression where a power is present. Therefore, \( \ln(5^2) = 2\ln(5) \) and \( \ln(5^3) = 3\ln(5) \). Now the expression becomes \( \ln(5) + 2\ln(5) + 3\ln(5) - \ln(5^6) \).
2Step 2: Combine Like Terms
We have multiple \( \ln(5) \) terms. Combine these using arithmetic addition: \( \ln(5) + 2\ln(5) + 3\ln(5) = (1+2+3)\ln(5) = 6\ln(5) \). Now, the expression simplifies to \( 6\ln(5) - \ln(5^6) \).
3Step 3: Apply the Power Rule Again
Apply the power rule to \( \ln(5^6) \) to rewrite it as \( 6\ln(5) \). The current form of the expression is \( 6\ln(5) - 6\ln(5) \).
4Step 4: Simplify the Expression
Use combining like terms again. Since \( 6\ln(5) - 6\ln(5) \) equals zero, the logarithmic expression simplifies to zero.
Key Concepts
Power Rule for LogarithmsCombining LogarithmsNatural Logarithm
Power Rule for Logarithms
The power rule is an exciting tool when working with logarithms. It allows you to bring down the exponent in a logarithmic expression as a multiplier. This means that if you have an expression like \( \ln(a^b) \), it can be rewritten as \( b \ln(a) \).
Here's why the power rule is so valuable:
This change is crucial because working with simple multiples is far easier than dealing with powers directly.
Always remember to check for exponents in log expressions and see if the power rule can be applied, making your calculations a breeze.
Here's why the power rule is so valuable:
- It simplifies expressions by turning powers into simple multiples.
- It makes complex logarithmic expressions easier to handle and manipulate.
This change is crucial because working with simple multiples is far easier than dealing with powers directly.
Always remember to check for exponents in log expressions and see if the power rule can be applied, making your calculations a breeze.
Combining Logarithms
Combining logarithms is another powerful technique to simplify expressions. Once you've applied the power rule, you often find terms that are similar and can be merged.
In our example expression, we have the summed terms \( \ln(5) + 2\ln(5) + 3\ln(5) \). By combining these, we add the coefficients of \( \ln(5) \), resulting in \( 6\ln(5) \).
In our example expression, we have the summed terms \( \ln(5) + 2\ln(5) + 3\ln(5) \). By combining these, we add the coefficients of \( \ln(5) \), resulting in \( 6\ln(5) \).
- Combine like terms to condense the expression.
- This step helps simplify and solve the problem efficiently.
Natural Logarithm
Natural logarithms, denoted as \( \ln \), are logarithms with the base \( e \), where \( e \approx 2.718 \). These are widely used in mathematics, especially in calculus, because of their unique properties related to exponential functions.
The symbol \( \ln \) is crucial because it sets the context of the base being \( e \), which is special in math for its naturally occurring nature.
The symbol \( \ln \) is crucial because it sets the context of the base being \( e \), which is special in math for its naturally occurring nature.
- \( e \) is an irrational number, making \( \ln \) distinct from other logarithms like base 10 or base 2.
- \( \ln \) simplifies many equations, especially those involving growth and decay processes.
Other exercises in this chapter
Problem 55
Find the \(x\) -intercepts of the graph of the given function. $$ f(x)=\frac{10}{2+e^{-2 x}}-1 $$
View solution Problem 55
The threshold of pain is generally taken to be around \(140 \mathrm{~dB}\). Find the intensity of sound \(I\) corresponding to \(140 \mathrm{~dB}\).
View solution Problem 56
Find the \(x\) -intercepts of the graph of the given function. $$ f(x)=\frac{2^{x}-6+2^{3-x}}{x+2} $$
View solution Problem 56
Use a graphing utility to graph the function \(f(x)\) \(=(1+x)^{1 / x}\) on the intervals \([0.1,1],[0.01,1],\) and \([0.001,1] .\) Describe the behavior of \(f
View solution