Problem 55
Question
In Exercises,Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. $$ \text { If } f^{\prime}(c) \text { and } g^{\prime}(c) \text { are zero and } h(x)=f(x) g(x) \text { , then } h^{\prime}(c)=0 . $$
Step-by-Step Solution
Verified Answer
The statement is true. The derivative of function \( h(x) \) at point \( c \) is indeed zero if both \( f'(c) \) and \( g'(c) \) are zero.
1Step 1: Clarifying Mathematical Concepts
Firstly recall the product rule of differentiation which states \( (f(x)g(x))' = f'(x)g(x) + f(x)g'(x) \). This rule will be essential in solving this problem.
2Step 2: Applying the product rule
Using the product rule on the function \( h(x) = f(x)g(x) \), differentiating with respect to \( x \), yields the formula \( h'(x) = f'(x)g(x)+f(x)g'(x) \). We then plug \( x = c \) into this formula to see if we get zero.
3Step 3: Substituting into Formula
Substituting the \( c \) into this formula we get \( h'(c) = f'(c)g(c) + f(c)g'(c) \) . Now, in the problem, it's mentioned that \( f'(c) \) and \( g'(c) \) are zero. Replacing these zero values into the formula results in \( h'(c) = 0*g(c) + f(c)*0 = 0 \).
4Step 4: Concluding the Solution
So, from the above steps, it's clear that the statement 'If \( f'(c) \) and \( g'(c) \) are zero and \( h(x) = f(x)g(x) \), then \( h'(c) = 0 \)' is true.
Key Concepts
Product RuleDerivativesFunction Analysis
Product Rule
The Product Rule is an essential concept when dealing with derivatives of functions that are products of two or more functions. When you multiply two functions and want to find the derivative of the resulting function, the product rule is your go-to tool. It helps you compute the derivative without having to expand the functions separately.
For example, if you have functions \( f(x) \) and \( g(x) \), their product \( h(x) = f(x) \cdot g(x) \) can be differentiated using the product rule as follows:
For example, if you have functions \( f(x) \) and \( g(x) \), their product \( h(x) = f(x) \cdot g(x) \) can be differentiated using the product rule as follows:
- Start by differentiating the first function: \( f'(x) \).
- Multiply \( f'(x) \) by the second function \( g(x) \).
- Then differentiate the second function: \( g'(x) \) and multiply it by the first function \( f(x) \).
- Add these results together to find \( h'(x) \): \( h'(x) = f'(x)g(x) + f(x)g'(x) \).
Derivatives
Derivatives are a fundamental concept in calculus that measure how a function changes as its input changes. Think of them as a way to find the slope of a function at any given point. This slope signifies how steep or flat the curve is at a specific location.
In mathematical terms, the derivative of a function \( f(x) \) is represented as \( f'(x) \).
Here's why derivatives are important:
In mathematical terms, the derivative of a function \( f(x) \) is represented as \( f'(x) \).
Here's why derivatives are important:
- They tell us the rate of change. For instance, in physics, a derivative could represent velocity, the rate of change of position with time.
- They help in finding the maximum and minimum points of a function, which is crucial in optimization problems.
- Understanding derivatives is critical for analyzing the behavior of complex models and functions.
Function Analysis
Function analysis is the process of understanding what a function represents, its output behaviors, and how its rate of change or slope evolves over a domain. This often involves differentiating the function, identifying key characteristics like intercepts, asymptotes, and extremums (maximum or minimum values).
In our example, the focus is on analyzing the function \( h(x) = f(x)g(x) \) through its derivative \( h'(x) \). We use critical points — where the derivatives are zero — to glean insights into the points where the function could achieve local maxima or minima. These critical points are vital to understanding the behavior of the function.
In our example, the focus is on analyzing the function \( h(x) = f(x)g(x) \) through its derivative \( h'(x) \). We use critical points — where the derivatives are zero — to glean insights into the points where the function could achieve local maxima or minima. These critical points are vital to understanding the behavior of the function.
- By evaluating the function's derivative, we are able to determine where the function is increasing or decreasing.
- We use analyses like these to make predictions about overall function behavior over small and large intervals.
- Particularly at \( x = c \), evaluating \( f'(c), g'(c) \) helps to interpret the importance of zero derivative values at this specific point in the context of the product rule.
Other exercises in this chapter
Problem 54
$$ \begin{aligned} &f(0)=f(2)=0 \\ &f^{\prime}(x)0 \text { if } x>1 \\ &f^{\prime \prime}(x)>0 \end{aligned} $$
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In Exercises,Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. $$ \text { If } y=(x+1)(x+
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In Exercises,Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. The second derivative repr
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In Exercises, you are given \(f^{\prime}\). Find the intervals on which (a) \(f^{\prime}(x)\) is increasing or decreasing and (b) the graph of \(f\) is concave
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