Problem 55
Question
For which equation is \(j=4\) a solution? $$ \begin{aligned} &\text{(F)}\quad -10+5 j=-2+2 j &\text{(G)}\quad 7 j-3 j+2=4 j-2\\\ &\text{(H)}\quad 6 j-4=4 j+4 &\text{(J)}\quad 63 j+7=2 j-2 \end{aligned} $$
Step-by-Step Solution
Verified Answer
The equation for which \(j=4\) is a solution, is equation (H).
1Step 1: Substitution into equation (F)
Substitute \(j=4\) into the equation (F): \[-10+5(4)=-2+2(4)\] Simplify both sides: \[-10+20=-2+8\] After simplification, both sides give: \(10=6\). This equation does not hold true, so \(j=4\) is not a solution to equation (F).
2Step 2: Substitution into equation (G)
Substitute \(j=4\) into the equation (G): \[7(4)-3(4)+2=4(4)-2\] Simplify both sides: \[28-12+2=16-2\] After simplification, both sides give: \(18=14\). This equation does not hold true, so \(j=4\) is not a solution to equation (G).
3Step 3: Substitution into equation (H)
Substitute \(j=4\) into the equation (H): \[6(4)-4=4(4)+4\] Simplify both sides: \[24-4=16+4\] After simplification, both sides give: \(20=20\). This equation holds true, so \(j=4\) is a solution to equation (H). There is no need to check the remaining equation (J) as we've found our answer.
Key Concepts
Algebraic EquationsSubstitution MethodEquation Simplification
Algebraic Equations
Algebraic equations are the cornerstone of solving mathematical problems. They link variables with operations and constants to form statements that can represent real-world scenarios, mathematical models, or puzzles to be solved. In essence, they are the language through which we communicate quantitative relationships.
At its core, an algebraic equation is a statement of equality that includes one or more unknowns—commonly represented by letters like `j` in our exercise example. These equations come in varied forms, ranging from simple, one-variable linear equations to more complex polynomials or systems of equations with multiple variables. The end goal with these equations is to find the value or set of values that satisfy the statement of equality, which we call the solution.
In the given exercise, we encounter several simple linear equations with the variable `j`. Our objective is to determine for which equation `j=4` is the solution, a process which involves various algebra techniques, like the substitution method and equation simplification.
At its core, an algebraic equation is a statement of equality that includes one or more unknowns—commonly represented by letters like `j` in our exercise example. These equations come in varied forms, ranging from simple, one-variable linear equations to more complex polynomials or systems of equations with multiple variables. The end goal with these equations is to find the value or set of values that satisfy the statement of equality, which we call the solution.
In the given exercise, we encounter several simple linear equations with the variable `j`. Our objective is to determine for which equation `j=4` is the solution, a process which involves various algebra techniques, like the substitution method and equation simplification.
Substitution Method
The substitution method is an effective tool for solving equations, especially when we have a given value for a variable. It involves replacing the variable with its known value and simplifying the equation to check if the equality holds.
To use this method
In step by step terms, when we input `j=4` into equation (H), we transform the abstract statement `6j-4=4j+4` into the concrete statement `20=20`, which is a true equality. Therefore, by using the substitution method effectively, we can conclude that `j=4` is indeed a solution for equation (H).
To use this method
- Identify the known value of the variable.
- Substitute that value into the equation in place of the variable.
- Simplify the equation to check for true equality.
In step by step terms, when we input `j=4` into equation (H), we transform the abstract statement `6j-4=4j+4` into the concrete statement `20=20`, which is a true equality. Therefore, by using the substitution method effectively, we can conclude that `j=4` is indeed a solution for equation (H).
Equation Simplification
Simplifying an equation is a process that helps us distill the essence of the relationship expressed by the equation. It involves applying mathematical operations to both sides of the equation to make it easier to read and solve.
Simplification can involve
The power of equation simplification lies in its ability to transform equations into simpler forms, which are often much easier to evaluate for truthfulness or to solve for the remaining unknowns.
Simplification can involve
- Combining like terms—terms in the equation with the same variable to the same power.
- Applying the distributive property—when a number multiplies an entire sum or difference.
- Reducing fractions or moving terms from one side of the equality to the other to isolate the variable.
The power of equation simplification lies in its ability to transform equations into simpler forms, which are often much easier to evaluate for truthfulness or to solve for the remaining unknowns.
Other exercises in this chapter
Problem 55
Find the opposite of the number. $$ -3 $$
View solution Problem 55
MULTIPLE CHOICE Solve \(-\frac{5}{7} x=-2\). F. \(\frac{14}{5}\) G. \(-\frac{14}{5}\) H. \(\frac{10}{7}\) J. \( \frac{7}{5}\)
View solution Problem 55
In Exercises 54–56, match the real-life problem with an equation. Then solve the problem. A. \(x+15=7\) B. \(15-x=7\) C. \(15+7=x\) D. \(x+15=-7\) There are 15
View solution Problem 56
Find the least common denominator of the pair of fractions. $$\frac{3}{4}, \frac{2}{5}$$
View solution