Problem 55
Question
For the following problems, factor the binomials. $$ x^{12}-y^{12} $$
Step-by-Step Solution
Verified Answer
$$
Answer: The factored form of the expression $$x^{12} - y^{12}$$ is $(x^6 + y^6)((x^3 + y^3)(x^3 - y^3))$.
1Step 1: Identify the Difference of Squares
Given the expression $$x^{12} - y^{12},$$ we can rewrite it as $$(x^6)^2 - (y^6)^2$$ to highlight that it is a difference of squares.
2Step 2: Apply the Difference of Squares Formula
Using the formula $$a^2 - b^2 = (a + b)(a - b),$$ we substitute \(a = x^6\) and \(b = y^6\):
$$
(x^6)^2 - (y^6)^2 = (x^6 + y^6)(x^6 - y^6)
$$
3Step 3: Further Factor if Possible
Now, we see that the expression \(x^6 - y^6\) is also a difference of squares. We can rewrite it as $$(x^3)^2 - (y^3)^2$$ and apply the difference of squares formula again:
$$
(x^3)^2 - (y^3)^2 = (x^3 + y^3)(x^3 - y^3)
$$
Finally, we put everything back together:
$$
x^{12} - y^{12} = (x^6 + y^6)((x^3 + y^3)(x^3 - y^3))
$$
Key Concepts
Difference of SquaresAlgebraic ExpressionsFactoring Techniques
Difference of Squares
The concept of the difference of squares is a fundamental idea in algebra. It refers to a binomial expression that takes the form of \( a^2 - b^2 \). This concept is crucial because it can be factored into two simpler binomial expressions through a special factoring technique. The formula used is \( a^2 - b^2 = (a + b)(a - b) \). This allows us to break down complex expressions into simpler parts.
In our example problem, \( x^{12} - y^{12} \), we first express each term as a square: \( (x^6)^2 - (y^6)^2 \). Recognizing this as a difference of squares, we can apply our formula:
In our example problem, \( x^{12} - y^{12} \), we first express each term as a square: \( (x^6)^2 - (y^6)^2 \). Recognizing this as a difference of squares, we can apply our formula:
- \( (x^6)^2 - (y^6)^2 = (x^6 + y^6)(x^6 - y^6) \)
Algebraic Expressions
Algebraic expressions are a combination of numbers, variables, and operators. They form the basis of algebra and are used to represent mathematical ideas in a symbolic form. Each part of an expression holds specific meaning and follows certain rules.
In our example, the expression \( x^{12} - y^{12} \) comprises two terms: \( x^{12} \) and \( y^{12} \). Both terms involve variables raised to a power, indicating repeated multiplication. Such expressions can often be simplified or manipulated using various algebraic rules and techniques—factoring is one prominent technique.
Understanding the structure and components of algebraic expressions makes them easier to manipulate, reduce, and solve. This foundational knowledge enables you to tackle more complex problems by breaking them down into comprehensible parts.
In our example, the expression \( x^{12} - y^{12} \) comprises two terms: \( x^{12} \) and \( y^{12} \). Both terms involve variables raised to a power, indicating repeated multiplication. Such expressions can often be simplified or manipulated using various algebraic rules and techniques—factoring is one prominent technique.
Understanding the structure and components of algebraic expressions makes them easier to manipulate, reduce, and solve. This foundational knowledge enables you to tackle more complex problems by breaking them down into comprehensible parts.
Factoring Techniques
Factoring is a powerful technique used to simplify algebraic expressions or solve equations. When you factor an expression, you express it as a product of simpler expressions, or factors, which when multiplied together give the original expression back.
In our exercise, the expression \( x^{12} - y^{12} \) is factored by recognizing it as a difference of squares first. The goal is to keep breaking it down using known identities or techniques until it cannot be factored further with ease:
In our exercise, the expression \( x^{12} - y^{12} \) is factored by recognizing it as a difference of squares first. The goal is to keep breaking it down using known identities or techniques until it cannot be factored further with ease:
- First factor: \( (x^6 + y^6)(x^6 - y^6) \)
- Further breaking down: \( (x^3 + y^3)(x^3 - y^3) \) from the second term \( x^6 - y^6 \)
Other exercises in this chapter
Problem 54
For the following problems, factor the trinomials if possible. $$ 14 a^{2} z^{2}-40 a^{3} z^{2}-46 a^{4} z^{2} $$
View solution Problem 55
For the following problems, factor the polynomials, if possible. $$ 4 a^{2}-9 a-9 $$
View solution Problem 55
Simplify \(\left(a^{3} b^{6}\right)^{4}\)
View solution Problem 56
For the following problems, factor the polynomials, if possible. $$ 4 x^{2}+7 x+3 $$
View solution