Problem 55
Question
Find the limits. $$\lim _{x \rightarrow 0^{+}} x^{-1 / \ln x}$$
Step-by-Step Solution
Verified Answer
The limit is \( e^{-1} \).
1Step 1: Recognize the Indeterminate Form
Observe that as \( x \rightarrow 0^+ \), both \( x^{-1 / \ln x} \) and \( \ln x \) approach indeterminate forms. \( \ln x \rightarrow -\infty \) and \( -1 / \ln x \rightarrow 0 \), making \( x^{-1/\ln x} = e^{\ln(x^{-1/\ln x})} \) an indeterminate form of type \( 0^0 \).
2Step 2: Use Logarithmic Transformation
Set \( y = x^{-1/\ln x} \), and take the natural logarithm of both sides: \( \ln y = -\frac{1}{\ln x} \cdot \ln x = -\frac{\ln x}{\ln x} = -1 \). This simplification reveals a constant in the exponent.
3Step 3: Analyze the Exponential Form
Since \( \ln y = -1 \), then \( y = e^{-1} \) as \( x \rightarrow 0^+ \). Therefore, the limit of the original expression \( x^{-1/\ln x} \) is determined by noting that it converges to \( e^{-1} \).
4Step 4: Conclusion about the Limit
Thus, the limit \( \lim_{x \rightarrow 0^+} x^{-1/\ln x} \) is equal to \( e^{-1} \). This solves the initial indeterminate form.
Key Concepts
Indeterminate FormsLogarithmic TransformationExponential Growth
Indeterminate Forms
When we talk about indeterminate forms in calculus, we're referring to expressions that do not have a clear limit or value at first glance. These forms typically appear in limit problems, such as when evaluating the limit of a function as it approaches a certain point where it is not initially clear what the outcome will be. Common examples include forms like \(0/0\), \(\infty/\infty\), \(0^0\), and several others.
When you encounter an indeterminate form, it requires further analysis or transformation to simplify or resolve the expression. In our exercise, as \( x \to 0^+ \), \( x^{-1/\ln x} \) needs to be carefully examined due to the presence of the \(0^0\) form. Tackling such forms often involves using further techniques such as algebraic manipulation or applying the properties of logarithms and exponents. Recognizing and dealing with indeterminate forms is essential in understanding limits and the behavior of functions near specific points.
When you encounter an indeterminate form, it requires further analysis or transformation to simplify or resolve the expression. In our exercise, as \( x \to 0^+ \), \( x^{-1/\ln x} \) needs to be carefully examined due to the presence of the \(0^0\) form. Tackling such forms often involves using further techniques such as algebraic manipulation or applying the properties of logarithms and exponents. Recognizing and dealing with indeterminate forms is essential in understanding limits and the behavior of functions near specific points.
Logarithmic Transformation
Logarithmic transformations are powerful tools for simplifying complex expressions, especially when exponents are involved. In this exercise, a logarithmic transformation is used to simplify \( x^{-1/\ln x} \). By introducing a new variable \( y = x^{-1/\ln x} \) and considering its natural logarithm, we convert the expression into a form that reveals its true nature.
By taking the natural logarithm, we turn the exponential expression into a product: \( \ln y = -\frac{\ln x}{\ln x} = -1 \). This conversion drastically simplifies the problem by translating the indeterminate form into something manageable.
By taking the natural logarithm, we turn the exponential expression into a product: \( \ln y = -\frac{\ln x}{\ln x} = -1 \). This conversion drastically simplifies the problem by translating the indeterminate form into something manageable.
- Logarithms help reduce the complexity of problems and can convert multiplication into addition, division into subtraction, and exponents into coefficients.
- In calculus, logarithmic transformations can turn difficult limit problems into simple algebraic manipulations.
Exponential Growth
Exponential functions, characterized by expressions of the form \( e^{x} \), play a crucial role in modeling growth and decay processes in nature. However, when used in calculus to find limits, they often reveal behaviors of functions as variables approach certain points.
In our example, we analyze the behavior of \( x^{-1/\ln x} \) which elegantly resolves into an exponential form \( e^{-1} \) by using logarithms to simplify and reveal the constant hidden in the expression.
This transformation shows that as \( x \to 0^+ \), the limit isn't some elusive indeterminate result but rather becomes a well-defined number \( e^{-1} \), demonstrating the sophisticated power of exponential calculations.
In our example, we analyze the behavior of \( x^{-1/\ln x} \) which elegantly resolves into an exponential form \( e^{-1} \) by using logarithms to simplify and reveal the constant hidden in the expression.
This transformation shows that as \( x \to 0^+ \), the limit isn't some elusive indeterminate result but rather becomes a well-defined number \( e^{-1} \), demonstrating the sophisticated power of exponential calculations.
- When faced with such functions, recognizing transformations that reveal a simpler exponential relationship is key.
- Exponential growth and decay aren't just mathematical curiosities; they are fundamental behaviors encountered across different scientific fields.
- Grasping how to manage exponential terms in limit problems will give you deeper insights into the seamless transition between apparent complexity and underlying simplicity.
Other exercises in this chapter
Problem 55
Show that if \(r(x)=6 x\) and \(c(x)=x^{3}-6 x^{2}+15 x\) are your revenue and cost functions, then the best you can do is break even (have revenue equal cost).
View solution Problem 55
a. Identify the function's local extreme values in the given domain, and say where they occur. b. Which of the extreme values, if any, are absolute? c. Support
View solution Problem 56
Identify the coordinates of any local and absolute extreme points and inflection points. Graph the function. $$y=\frac{\ln x}{\sqrt{x}}$$
View solution Problem 56
Find the extreme values (absolute and local) of the function over its natural domain, and where they occur. $$y=x^{3}(x-5)^{2}$$
View solution