Problem 55
Question
Factor completely. $$ 54 x 4 y-2 x y 4 $$
Step-by-Step Solution
Verified Answer
The expression factors to \( 2xy(3x - y)(9x^2 + 3xy + y^2) \).
1Step 1: Simplify the Expression
First, let's rewrite the given expression stepping through any confusion due to formatting and symbols. We have:\[ 54x^4y - 2xy^4 \]
2Step 2: Factor Out the Greatest Common Factor (GCF)
Identify the greatest common factor for the terms in the expression. Here, the GCF is \( 2xy \). Factor \( 2xy \) out of each term:\[ 54x^4y = 2xy imes 27x^3 \]\[ 2xy^4 = 2xy imes y^3 \]Thus, we can factor out the GCF:\[ 2xy(27x^3 - y^3) \]
3Step 3: Recognize the Difference of Cubes
The expression inside the parentheses \( 27x^3 - y^3 \) is a difference of cubes. This allows further factoring using the difference of cubes formula:\[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \]Here, let \( a = 3x \) and \( b = y \), then apply the formula.
4Step 4: Apply the Difference of Cubes Formula
Substitute \( a = 3x \) and \( b = y \) into the difference of cubes formula and factor:\[ 27x^3 - y^3 = (3x - y)((3x)^2 + 3x imes y + y^2) \]Compute the expression:\[ = (3x - y)(9x^2 + 3xy + y^2) \]
5Step 5: Final Answer: Combine All Factors
Combine all parts to present the fully factored expression:\[ 54x^4y - 2xy^4 = 2xy(3x - y)(9x^2 + 3xy + y^2) \]
Key Concepts
Greatest Common FactorDifference of CubesAlgebraic Expressions
Greatest Common Factor
When factoring polynomials, the greatest common factor (GCF) is the largest term that can be evenly divided from all terms of the polynomial. Identifying the GCF is the first step in the factoring process and can simplify the expression.
To find the GCF, look for numerical coefficients and variables common to each term of the polynomial. In the example given, we have two terms:
By factoring out the GCF, the expression becomes simpler, allowing easier manipulation or further factoring, as shown in subsequent steps.
To find the GCF, look for numerical coefficients and variables common to each term of the polynomial. In the example given, we have two terms:
- 54x^4y
- 2xy^4
By factoring out the GCF, the expression becomes simpler, allowing easier manipulation or further factoring, as shown in subsequent steps.
Difference of Cubes
The difference of cubes formula is a handy tool in algebra that allows us to factor specific types of polynomial expressions. It is applicable when you encounter the subtraction of two perfect cubes.
The formula is:\[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \]
Recognizing when this formula can be used is crucial. In our example, after factoring out the GCF, we are left with \( 27x^3 - y^3 \), which matches the structure of a^3 - b^3.
This breaks down the expression into a binomial \((3x - y)\) and a trinomial \((9x^2 + 3xy + y^2)\), completing the factorization process.
The formula is:\[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \]
Recognizing when this formula can be used is crucial. In our example, after factoring out the GCF, we are left with \( 27x^3 - y^3 \), which matches the structure of a^3 - b^3.
- Here, 27x^3 is the cube of 3x (since \((3x)^3 = 27x^3\)).
- Similarly, y^3 is the cube of y (as \(y^3 = y^3\)).
This breaks down the expression into a binomial \((3x - y)\) and a trinomial \((9x^2 + 3xy + y^2)\), completing the factorization process.
Algebraic Expressions
An algebraic expression is a combination of numbers, variables, and operators (such as +, –, *, /). These expressions are the foundation of algebra and are used to represent real-world problems and mathematical relationships.
Algebraic expressions can be manipulated through various operations, including simplifying, expanding, and factoring. Factoring, like in our example, involves breaking down expressions into products of simpler factors. Understanding how to manipulate these expressions is essential in solving equations, graphing functions, and more.
When dealing with algebraic expressions:
Algebraic expressions can be manipulated through various operations, including simplifying, expanding, and factoring. Factoring, like in our example, involves breaking down expressions into products of simpler factors. Understanding how to manipulate these expressions is essential in solving equations, graphing functions, and more.
When dealing with algebraic expressions:
- Identify the terms and coefficients.
- Use factoring techniques like the GCF or special formulas such as the difference of cubes.
- Reassemble the expression to its most simplified or desired form.
Other exercises in this chapter
Problem 55
An object is dropped from a ladder at a height of 16 feet. How long will it take to hit the ground?
View solution Problem 55
Factor completely. $$ 36-15 a-6 a 2 $$
View solution Problem 55
Solve. $$ (x+1) 2-25=0 $$
View solution Problem 55
Factor out the GCF. $$ 2 x(x-3)+5(x-3) $$
View solution