Problem 55
Question
Evaluate each expression. $$ \begin{array}{ll}{\text { (a) }| |-6|-|-4| |} & {\text { (b) } \frac{-1}{|-1|}}\end{array} $$
Step-by-Step Solution
Verified Answer
(a) 2; (b) -1.
1Step 1: Evaluate the Expression for (a)
We start with the expression for (a): \[| |-6|-|-4| |\]First, evaluate the absolute values inside the innermost brackets:\[|-6| = 6 \quad \text{and} \quad |-4| = 4\]Substitute these back into the expression:\[|6 - 4|\]Then, calculate the subtraction:\[|6 - 4| = |2|\]Finally, take the absolute value:\[|2| = 2\]So, the result of the expression for (a) is 2.
2Step 2: Evaluate the Expression for (b)
Now consider the expression for (b): \[\frac{-1}{|-1|}\]First, calculate the absolute value in the denominator:\[|-1| = 1\]Substitute this value back into the expression:\[\frac{-1}{1} = -1\]Thus, the result of the expression for (b) is -1.
Key Concepts
Expression EvaluationSubtractionDivision
Expression Evaluation
Expression evaluation involves assessing mathematical expressions by simplifying and applying known operations step-by-step. It is crucial to follow the correct order of operations to obtain the correct result. When evaluating expressions, especially those with absolute values, it's important to deal with the absolute value brackets first. Here’s a quick reminder of the basic rules:
- Start by simplifying the expression inside the absolute value brackets.
- Apply operations such as subtraction or division within the absolute value first.
- After operations within the absolute values are handled, simplify the expression further if needed.
- Finally, apply the absolute value, which always makes the result non-negative.
Subtraction
Subtraction is one of the core arithmetic operations where you are essentially taking away or "subtracting" one number from another. When working with subtraction in an expression, it’s vital to pay attention to the numbers involved and handle any additional operations like absolute values correctly.
In our exercise, subtraction was used within absolute values. Initially, we simplified \( |6 - 4| \) by evaluating the difference between 6 and 4, resulting in 2. Here are some tips for handling subtraction effectively:
In our exercise, subtraction was used within absolute values. Initially, we simplified \( |6 - 4| \) by evaluating the difference between 6 and 4, resulting in 2. Here are some tips for handling subtraction effectively:
- Always subtract smaller numbers from larger numbers when in an absolute value to keep expressions non-negative.
- Remember that subtraction changes the direction on the number line; be careful with negative numbers.
- After performing subtraction, if the subtraction is within an absolute value, apply the absolute value to ensure the result is non-negative.
Division
Division is the process of splitting a number into equal parts. In an expression, division must be performed following any evaluation or simplification of absolute values. For normal division, remember that dividing by a positive number keeps the sign of the numerator, whereas dividing by a negative number changes the sign.
When dealing with an expression like the one in part (b) where you have \( \frac{-1}{|-1|} \):
When dealing with an expression like the one in part (b) where you have \( \frac{-1}{|-1|} \):
- First, calculate the absolute value of the denominator.
- With \( |-1| = 1 \), substitute it back to get the expression: \( \frac{-1}{1} \).
- Now, perform the division: \( \frac{-1}{1} = -1 \).
Other exercises in this chapter
Problem 55
\(47-72\) . Simplify the expression, and eliminate any negative exponent(s). $$ (r s)^{-2}\left(2 r s^{2}\right)^{3} $$
View solution Problem 55
Factor the expression completely. $$ 4 x^{2}+4 x y+y^{2} $$
View solution Problem 55
\(49-68=\) Simplify the expression and eliminate any negative exponent(s). Assume that all letters denote positive numbers. $$ \left(8 a^{6} b^{3 / 2}\right)^{2
View solution Problem 55
Multiply the algebraic expressions using a Special Product Formula, and simplify. \((2 x+3 y)^{2}\)
View solution