Problem 54
Question
Use the following information. You and a friend go hiking. You hike 3 miles north and 2 miles west. Starting from the same point, your friend hikes 4 miles east and 1 mile south. How far apart are you and your friend? (Hint: Draw a diagram on a grid.)
Step-by-Step Solution
Verified Answer
Based on the solution steps, the distance between you and your friend is approximately 4.47 miles.
1Step 1: Represent the Paths on a Graph
Visualising problems can often make them easier to understand. Start by representing yours and your friend's path on a Cartesian plane or grid. Let's say the starting point is the origin (0,0). Your pathway can be represented by the vector (2,3) and your friend's by (4,-1) which means, You end up at the point (2,3) and your friend at the point (4,-1).
2Step 2: Calculate the Difference in x and y Coordinates
The difference in the x coordinates between your and your friend's final positions is: \(dx = x_2 - x_1 = 4 - 2 = 2\). The difference in the y coordinates between your and your friend's final positions is: \(dy = y_2 - y_1 = -1 - 3 = -4\). These values dx (horizontal distance) and dy (vertical distance) represent the sides of a right triangle where the distance we want to calculate is the hypotenuse.
3Step 3: Apply Pythagorean Theorem
The Pythagorean theorem states that for any right triangle with sides of lengths a, b (dx and dy in our case), and c (hypotenuse), the relationship between these lengths is: \(a^2 + b^2 = c^2\). Substituting the dx and dy values, we get: \(c^2 = 2^2 + (-4)^2 = 4 + 16 = 20\). Hence, \(c = \sqrt{20} \approx 4.47\) miles.
Key Concepts
Pythagorean TheoremCoordinate GraphingVectors
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in geometry that helps us find the length of the hypotenuse in a right-angled triangle. The theorem states that the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. Written as an equation, it looks like this: \( a^2 + b^2 = c^2 \). Here, \( a \) and \( b \) are the lengths of the triangle's legs and \( c \) is the hypotenuse. Applying this theorem is crucial when solving distance-related problems in a coordinate system.
- Step-by-step usage: Identify the two shorter sides of your right triangle (often represented by line segments on a graph).
- Calculate the square of each side, sum the squares, and finally find the square root of this sum to determine the hypotenuse.
Coordinate Graphing
Coordinate graphing provides us with a visual way to solve problems involving positions and distances. A coordinate plane consists of two perpendicular axes, labeled the x-axis (horizontal) and y-axis (vertical). Any point on this plane is represented by a pair of numbers known as coordinates, \( (x, y) \). In our hiking scenario, the starting point \( (0, 0) \) was given, which is the origin of the graph.
- How to plot points: To plot a point, move along the x-axis to the x-coordinate and then move parallel to the y-axis to the y-coordinate.
- Understanding movement: When you hike north or south, you change your y-coordinate; going north increases it, while going south decreases it. East and west movements change the x-coordinate; east increases it, while west decreases it.
Vectors
Vectors are a powerful mathematical construct used to represent quantities that have both magnitude and direction. A vector is typically represented in a coordinate plane as an arrow pointing from one point to another. In the context of hiking, vectors help illustrate the change in position on the graph.
- Representation: A vector \( \vec{v} \) from point \( (0,0) \) to \( (x,y) \) is written as \( \langle x, y \rangle \).
- Operations: Vectors can be added together to find a resultant vector, showing overall movement, or subtracted to find the difference, such as in our original exercise where we subtract coordinates to find \( dx \) and \( dy \).
Other exercises in this chapter
Problem 53
Solve the quadratic equation. $$x^{2}-4 x-6=0$$
View solution Problem 53
Choose a method to solve the quadratic equation. Explain your choice. $$9 a^{2}-25=0$$
View solution Problem 54
Find the domain and the range of the function. Then sketch the graph of the function. $$y=2 \sqrt{4 x+10}$$
View solution Problem 54
Plot the ordered pairs in a coordinate plane. $$(1,3),(-3,1),(3,-4)$$
View solution