Problem 54
Question
Use the Binomial Theorem to expand and simplify the expression. \(-5(x+2)^{5}-2(x-1)^{2}\)
Step-by-Step Solution
Verified Answer
The expanded and simplified expression of \(-5(x+2)^{5}-2(x-1)^{2}\) is \(-5x^{5} - 50x^{4} - 200x^{3} - 402x^{2} - 396x - 162\).
1Step 1: Expand the First Term
Apply the binomial theorem to expand the expression \(-5(x+2)^{5}\). Each term in the expansion follows the pattern \(-5 \* \binom{5}{k} \* x^{5−k} \* 2^{k}\), where k is the position of the term, and the binomial coefficient \(\binom{5}{k} = \frac{5!}{k!(5−k)!}\). Expand this to obtain \(-5x^{5} - 50x^{4} - 200x^{3} - 400x^{2} - 400x -160\).
2Step 2: Expand the Second Term
Follow the same process for \(-2(x-1)^{2}\), resulting in the expansion \(-2x^{2} + 4x - 2\).
3Step 3: Combine Terms
Sum the expanded expressions from the previous steps: \(-5x^{5} - 50x^{4} - 200x^{3} - 400x^{2} - 400x - 160 - 2x^{2} + 4x - 2\)
4Step 4: Simplify Expression
Combine like terms to simplify the expression, and yield the final simplified expression: \(-5x^{5} - 50x^{4} - 200x^{3} - 402x^{2} - 396x - 162\)
Key Concepts
Expanding ExpressionsPolynomial CoefficientsCombining Like Terms
Expanding Expressions
Expanding expressions using the Binomial Theorem can feel like opening a magical box full of terms. This process allows us to transform expressions like \((x+2)^5\) into a long polynomial. The Binomial Theorem helps to break out each term systematically. To expand, identify the structure as \((a+b)^n\), where \(a\) and \(b\) represent distinct terms of the binomial, and \(n\) is the power to which they are raised. The theorem generates terms using the format \( \binom{n}{k} a^{n-k} b^k \), where \(k\) begins at 0 and ends at \(n\). Each term gets multiplied by a binomial coefficient and respective powers of \(a\) and \(b\). Studying each part can help:
- Increase efficiency in expanding binomials.
- Identify patterns in the resulting polynomial.
- Improve accuracy by systematically applying the theorem.
Polynomial Coefficients
Polynomial coefficients are critical elements when expanding expressions. They dictate the "weight" of each term. In binomial expansions, these coefficients come from binomial coefficients \(\binom{n}{k}\), calculated using factorials.Remember, factorials represent the product of all positive integers up to a given number. This provides a way to determine the combinatorial aspect of the coefficients. In our case, each term of \(-5(x+2)^5\) gets multiplied by such binomial coefficients. For every position \(k\), \(\binom{5}{k}\) is calculated to determine how many times that particular term configuration appears. This is essential for:
- Precise calculation of the polynomial's components.
- Avoiding mistakes by systematically using combinatorial math.
- Increasing algebraic manipulation skills.
Combining Like Terms
Combining like terms is the final polishing step in simplifying expanded polynomials. Once you've whipped out all terms with the help of expansions, the next goal is to streamline them. Like terms are terms with the same variable raised to the same power. For example, terms like \(-400x^2\) and \(-2x^2\) can be combined.Combining involves:
- Adding or subtracting the coefficients of like terms.
- Ensuring all terms are reduced to their simplest form.
- Checking and rechecking accuracy in combined values.
Other exercises in this chapter
Problem 54
A random number generator selects three numbers from 1 through 10. Find the probability of the event. All three numbers are greater than or equal to \(9 .\)
View solution Problem 54
Finding a Sequence of Partial Sums Use a graphing utility to create a table showing the sequence of the first 10 partial sums \(S_{1}, S_{2}, S_{3}, \ldots\) an
View solution Problem 55
Write the first five terms of the sequence defined recursively. $$a_{1}=3, a_{k+1}=2\left(a_{k}-1\right)$$
View solution Problem 55
Use the table feature of a graphing utility to find the first 10 terms of the sequence. (Assume \(n\) begins with 1.) $$a_{n}=1.5+0.05 n$$
View solution