Problem 54
Question
Two elements in the second transition series ( \(Y\) through Cd) have four unpaired electrons in their \(3+\) ions. What elements fit this description?
Step-by-Step Solution
Verified Answer
The elements are Molybdenum (Mo) and Technetium (Tc).
1Step 1: Identify the Second Transition Series
The second transition series consists of elements from Yttrium (\(Y\)) to Cadmium (\(Cd\)). These elements fill the 4d subshell in the periodic table.
2Step 2: Determine the Electron Configuration of the Neutral Atoms
List the electron configurations of the neutral atoms. For example, \(Y: [Kr] 4d^1 5s^2\), \(Zr: [Kr] 4d^2 5s^2\), \(Nb: [Kr] 4d^4 5s^1\), etc.
3Step 3: Consider the Ionization Process to Form 3+ Ions
In the formation of \(3^+\) ions, three electrons are removed, typically from the outermost \(s\) and \(d\) orbitals.
4Step 4: Calculate the 3+ Ion Configuration
Remove three electrons from each element: from the \(s\) and then the \(d\) subshells if needed. For example, \(Y^{3+}: [Kr] 4d^0\), \(Zr^{3+}: [Kr] 4d^1\), \(Nb^{3+}: [Kr] 4d^2\), etc.
5Step 5: Identify Elements with Four Unpaired Electrons
Check the ions to see which have four unpaired electrons. \(Mo^{3+}\) with configuration \([Kr] 4d^3\) and \(Tc^{3+}\) with \([Kr] 4d^4\) both have configurations that could satisfy this, and need further exploring for unpaired electron count.
Key Concepts
Electron ConfigurationIonization ProcessUnpaired ElectronsSecond Transition Series
Electron Configuration
Understanding electron configuration is crucial for grasping how transition metals interact and form ions. The electron configuration of an atom indicates the distribution of electrons in an atom's orbitals. For transition metals like Yttrium (\(Y\)) through Cadmium (\(Cd\)), the electrons primarily occupy the 4d subshell. Each element has a specific electron configuration reflecting its total number of electrons. For example, Yttrium (\(Y\)) is represented as \([Kr] 4d^1 5s^2\). Transition elements typically exhibit partially filled d-sublevels which lead them to have varied chemical properties. When dealing with transition series, we analyze how these electrons configure around each element to predict their behavior in different chemical contexts, such as ionization.
Ionization Process
The ionization process involves removing electrons from an atom to form a positive ion. For transition metals, this typically means removing the electrons from their highest energy orbitals first. When forming a \(3^+\) ion, three electrons are removed. These usually come from the s and d orbitals, starting with the outermost electrons:
- Electrons from the 5s orbital are removed first.
- Then, d orbital electrons are removed if needed to reach the \(3^+\) charge.
Unpaired Electrons
Unpaired electrons significantly influence the chemical properties of an element. In transition metals, unpaired electrons can affect magnetism and bonding capabilities. To find elements with four unpaired electrons, we examine the provided configurations after ionization. Each unpaired electron contributes to the total magnetic moment of the ion.For elements like \(Mo^{3+}\) with \[ [Kr] 4d^3 \], unpaired electrons are present in the d orbitals. In the case of \(Tc^{3+}\), with \[ [Kr] 4d^4 \], further analysis will confirm the electron's spin states to determine the presence of unpaired electrons. Identifying unpaired electrons is essential for understanding transition metals' behavior in various chemical environments.
Second Transition Series
The second transition series spans Yttrium (\(Y\)) through Cadmium (\(Cd\)). These elements are distinguished by the filling of the 4d subshell. This subshell configuration plays a crucial role in defining the unique chemical and physical properties of the series.In examining the periodic table:
- Elements transition from filling 5s orbitals to increasingly filling the 4d orbitals.
- Each element features a distinct electron arrangement that affects its chemical reactivity.
Other exercises in this chapter
Problem 52
The following are isoelectronic species: \(\mathrm{Cl}^{-}, \mathrm{K}^{+},\) and \(\mathrm{Ca}^{2+}\) Rank them in order of increasing (a) size, (b) ionization
View solution Problem 53
Compare the elements Na, B, Al, and C with regard to the following properties: (a) Which has the largest atomic radius? (b) Which has the most negative electron
View solution Problem 57
Why is the radius of \(\mathrm{Li}^{+}\) so much smaller than the radius of Li? Why is the radius of \(F^{-}\) so much larger than the radius of F?
View solution Problem 58
Which ions in the following list are not likely to be found in chemical compounds: \(\mathbf{K}^{2+}, \mathbf{C s}^{+}, \mathbf{A l}^{4+}, \mathbf{F}^{2-},\) an
View solution