Problem 54

Question

The points where the function \(f(x)=[x]+|1-x|,-1\) \(\leq x \leq 3\), where \([.]\) denotes the greatest integer function, is not differentiable, are (A) \(x=-1,0,1,2,3\) (B) \(x=-1,0,2\) (C) \(x=0,1,2,3\) (D) \(x=-1,0,1,2\)

Step-by-Step Solution

Verified
Answer
(A) \(x=-1, 0, 1, 2, 3\).
1Step 1: Understanding the Function's Components
The function is given by \( f(x) = [x] + |1-x| \), where \([.]\) denotes the greatest integer (floor) function and \(| \, |\) denotes the absolute value. To solve the problem, we need to identify where the function \( f(x) \) is not differentiable in the given interval \([-1, 3]\).
2Step 2: Analyzing the Greatest Integer Function
The greatest integer function \([x]\) is not differentiable at any integer because it has a jump at these points. Within the interval \([-1, 3]\), these points are \(-1, 0, 1, 2, 3\).
3Step 3: Analyzing the Absolute Value Term
The expression \(|1-x|\) is not differentiable at \(x=1\) because the derivative of an absolute value function does not exist where the argument is zero (where \(1-x=0\)).
4Step 4: Identifying Non-Differentiable Points
For \(f(x) = [x] + |1-x|\), non-differentiable points occur where either component \([x]\) or \(|1-x|\) is not differentiable. We have found that these points are \(-1, 0, 1, 2, 3\).
5Step 5: Choosing the Correct Multiple Choice Answer
Checking the options, option (A) states \(x = -1, 0, 1, 2, 3\) which matches all the points found in the analysis. Therefore, option (A) is the correct answer.

Key Concepts

Greatest Integer FunctionAbsolute Value FunctionNon-differentiable Points
Greatest Integer Function
The greatest integer function, also called the floor function, is denoted by \([x]\). This function outputs the largest integer less than or equal to \(x\). For example, * \([3.7] = 3\) * \([-2.1] = -3\) It's important to note that the greatest integer function is not continuous at integer points, and this is where it becomes non-differentiable. For the greatest integer function, non-differentiability occurs at every integer value because the function has a sudden jump at those places. Imagine trying to draw the function on graph paper: you would have to lift your pencil and move it vertically to the next point to continue. This discrete jump indicates the absence of a tangent, and thus a derivative, at those integer values. Within the interval \([-1, 3]\), it is non-differentiable at the integers \(-1, 0, 1, 2,\) and \(3\).
Absolute Value Function
The absolute value function portrays how far a number is from zero on the number line. Represented as \(|x|\), it returns the non-negative magnitude of \(x\), regardless of its sign. Here's how it behaves: * If \(x\) is positive or zero, \(|x| = x\). * If \(x\) is negative, \(|x| = -x\). In this exercise, we work with \(|1-x|\), which means the expression changes based on whether \(1-x\) is positive or negative. This implies a potential discontinuity in the slope, making the derivative non-existent at the point where the value inside the absolute value equals zero.For \(f(x) = [x] + |1-x|\), the term \(|1-x|\) becomes zero at \(x = 1\). This is where the function's slope changes abruptly, causing non-differentiability at this point.
Non-differentiable Points
Non-differentiable points occur where a function does not have a well-defined tangent line. This happens due to discontinuities, sharp corners, or cusps in the function's graph. In this exercise, the function \(f(x) = [x] + |1-x|\) is examined for non-differentiability over the interval \([-1, 3]\). Here, non-differentiability stems from two separate parts of the function:- The greatest integer function \([x]\) has jumps at integer values, and is non-differentiable at \(-1, 0, 1, 2,\) and \(3\). - The absolute value function \(|1-x|\) presents a sharp point at \(x = 1\), making it non-differentiable there.Thus, the points \(-1, 0, 1, 2,\) and \(3\) are collectively identified as non-differentiable for \(f(x)\). These points indicate changes in the function which prevent the calculation of a tangent line, confirming non-differentiability. The correct answer is hence option (A), covering all these critical points.