Problem 54
Question
The pOH of a sample of baking soda dissolved in water is 5.74 at \(25^{\circ} \mathrm{C}\). Calculate the \(\mathrm{pH},\left[\mathrm{H}^{+}\right],\) and \(\left[\mathrm{OH}^{-}\right]\) for this sample. Is the solution acidic or basic?
Step-by-Step Solution
Verified Answer
The pH of the sample is 8.26, the concentration of \(\mathrm{H}^{+}\) ions is \(5.5 \times 10^{-9}\) M, and the concentration of \(\mathrm{OH}^{-}\) ions is \(1.8 \times 10^{-6}\) M. Since the pH is greater than 7 and the concentration of \(\mathrm{OH}^{-}\) ions is greater than the concentration of \(\mathrm{H}^{+}\) ions, the solution is basic.
1Step 1: Calculate the pH
To calculate the pH of the sample, we will use the relationship between pH and pOH:
pH = 14 - pOH
Given the pOH is 5.74, we can calculate the pH as follows:
pH = 14 - 5.74 = 8.26
2Step 2: Calculate the concentration of \(\mathrm{H}^{+}\) ions
We will now calculate the concentration of \(\mathrm{H}^{+}\) ions using the relationship between pH and \(\mathrm{H}^{+}\) concentration:
pH = -log\(_{10}[\mathrm{H}^{+}]\)
We have the pH (8.26), so we can solve for \([\mathrm{H}^{+}]\):
\([\mathrm{H}^{+}]\) = 10\(^{-\mathrm{pH}}\) = 10\(^{-8.26}\) = 5.5 x 10\(^{-9}\) M
3Step 3: Calculate the concentration of \(\mathrm{OH}^{-}\) ions
To calculate the concentration of \(\mathrm{OH}^{-}\) ions, we will use the relationship between pOH and \(\mathrm{OH}^{-}\) concentration:
pOH = -log\(_{10}[\mathrm{OH}^{-}]\)
We have the pOH (5.74), so we can solve for \([\mathrm{OH}^{-}]\):
\([\mathrm{OH}^{-}]\) = 10\(^{-\mathrm{pOH}}\) = 10\(^{-5.74}\) = 1.8 x 10\(^{-6}\) M
4Step 4: Determine whether the solution is acidic or basic
A solution is considered acidic if the concentration of \(\mathrm{H}^{+}\) ions is greater than the concentration of \(\mathrm{OH}^{-}\) ions and pH < 7. A solution is considered basic if the concentration of \(\mathrm{OH}^{-}\) ions is greater than the concentration of \(\mathrm{H}^{+}\) ions and pH > 7. In our case:
pH = 8.26 (> 7)
\([\mathrm{H}^{+}]\) = 5.5 x 10\(^{-9}\) M
\([\mathrm{OH}^{-}]\) = 1.8 x 10\(^{-6}\) M
Since the pH is greater than 7 and the concentration of \(\mathrm{OH}^{-}\) ions is greater than the concentration of \(\mathrm{H}^{+}\) ions, the solution is basic.
Key Concepts
pH CalculationpOH CalculationConcentration of Ions
pH Calculation
When it comes to understanding pH calculation, it’s all about the balance between hydrogen ions, \( [\mathrm{H}^+] \), and hydroxide ions, \( [\mathrm{OH}^-] \). The pH scale is a way to measure how acidic or basic a solution is. This scale typically ranges from 0 to 14. A pH less than 7 indicates an acidic solution, and a pH greater than 7 indicates a basic solution. If the pH is exactly 7, the solution is neutral, like pure water.
To calculate the pH when you know the pOH, you use the equation:
To calculate the pH when you know the pOH, you use the equation:
- \( \mathrm{pH} = 14 - \mathrm{pOH} \)
- \( \mathrm{pH} = 14 - 5.74 = 8.26 \)
pOH Calculation
pOH is similar to pH, but rather than measuring the acidity, it measures how basic a solution is, focusing on the concentration of hydroxide ions, \( [\mathrm{OH}^{-}] \). The pOH scale also ranges from 0 to 14, where a low pOH signifies a highly basic solution.
The formula for finding the pOH from the concentration of hydroxide ions is:
The formula for finding the pOH from the concentration of hydroxide ions is:
- \( \mathrm{pOH} = -\log_{10}[\mathrm{OH}^{-}] \)
- \( [\mathrm{OH}^{-}] = 10^{-\mathrm{pOH}} \)
- \( [\mathrm{OH}^{-}] = 10^{-5.74} = 1.8 \times 10^{-6} \) M
Concentration of Ions
Understanding the concentration of ions in a solution is crucial in acid-base chemistry. These concentrations are often expressed in molarity (M), which is moles per liter of solution. Both \( [\mathrm{H}^{+}] \) and \( [\mathrm{OH}^{-}] \) concentrations can determine the nature of the solution, whether it's acidic or basic.
For a given pH, the concentration of hydrogen ions, \( [\mathrm{H}^{+}] \), can be calculated using the formula:
For a given pH, the concentration of hydrogen ions, \( [\mathrm{H}^{+}] \), can be calculated using the formula:
- \( [\mathrm{H}^{+}] = 10^{-\mathrm{pH}} \)
- \( [\mathrm{H}^{+}] = 10^{-8.26} = 5.5 \times 10^{-9} \) M
- \( [\mathrm{OH}^{-}] = 10^{-5.74} = 1.8 \times 10^{-6} \) M
Other exercises in this chapter
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