Problem 54
Question
The dimensional formula of magnetic flux is [BVP 2007] (a) \(\left[\mathrm{ML}^{0} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]\) (b) \(\left[\mathrm{ML}^{2} \mathrm{~T}^{-1} \mathrm{~A}^{-1}\right]\) (c) \(\left[\mathrm{ML}^{2} \mathrm{~T}^{-1} \mathrm{~A}^{-2}\right]\) (d) \(\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]\)
Step-by-Step Solution
Verified Answer
The correct answer is (d) \([ML^2 T^{-2} A^{-1}]\).
1Step 1: Understanding Magnetic Flux
Magnetic flux (Φ) is defined as the product of the magnetic field (B) and the area (A) it penetrates through, i.e., Φ = B * A. It measures how much the magnetic field passes through a given surface.
2Step 2: Dimensional Formula for Magnetic Field (B)
The dimensional formula of the magnetic field (B) can be derived from the Lorentz force law, which states that force (F) on a charge (q) moving with velocity (v) is F = qvB. Therefore, B = F/(qv). Now, force has dimensions [MLT^{-2}], charge (q) has dimensions [A^1 T^1] (from current, I=q/t), and velocity (v) has dimensions [LT^{-1}]. Thus, the dimensional formula for B becomes [M L^0 T^{-2} A^{-1}].
3Step 3: Dimensional Formula for Area (A)
Area is a measure of the extent of a surface and is given by the product of two lengths. Thus, the dimensional formula for area is [L^2].
4Step 4: Combining Magnetic Field and Area
Now, we multiply the dimensional formulas of magnetic field (B) and area (A) to get the dimensional formula of magnetic flux (Φ). Thus, Φ = B * A = [M L^0 T^{-2} A^{-1}] * [L^2] = [M L^2 T^{-2} A^{-1}].
5Step 5: Matching with the Options
Finally, we look at the given options and match our derived dimensional formula of magnetic flux [M L^2 T^{-2} A^{-1}] to the listed choices. This corresponds to option (d).
Key Concepts
Magnetic FluxMagnetic FieldLorentz Force LawDimensional FormulaPhysics Olympiad Problems
Magnetic Flux
Magnetic flux measures the total magnetic field passing through a specific area. Imagine it as the net amount of the magnetic field lines traversing through a surface.
- Mathematically, magnetic flux \( \Phi \) is given by \( \Phi = B \times A \), where \( B \) is the magnetic field strength and \( A \) is the area.
- It's crucial because it helps quantify how effective a particular magnetic field is in influencing physical systems.
- The unit of magnetic flux is the Weber (Wb) in the SI system.
Magnetic Field
A magnetic field is a region around a magnet where magnetic forces can be detected. It is an invisible field that exerts forces on particles that move through it.
- The magnetic field is often represented by field lines that show the field's direction and strength.
- It is denoted by \( B \) and is measured in Tesla (T).
- Both moving electric charges and magnetic dipoles (like bar magnets) create magnetic fields.
Lorentz Force Law
The Lorentz force law is fundamental in the realms of electromagnetism. It describes how charged particles experience a force when moving through an electric and magnetic field.
- The law is mathematically represented as \( F = q(E + v \times B) \), where \( F \) is the force on the particle, \( q \) is the electric charge, \( E \) is the electric field, and \( v \) is the velocity of the particle.
- This law explains phenomena such as the circular trajectories of charged particles in magnetic fields.
- It also underlies the working principles of many technologies, from cathode-ray tubes to particle accelerators.
Dimensional Formula
Dimensional formulas offer insight into the physical nature and dimensional analysis of physical quantities. They are expressions showing how fundamental units relate to derived units.
- For instance, in the problem at hand, the dimensional formula of magnetic flux is derived as \([M L^2 T^{-2} A^{-1}]\), revealing its components.
- Dimensional analysis helps verify equations and conversion between units.
- It assists in cross-checking the consistency of physical equations and can even predict relationships between different physical quantities.
Physics Olympiad Problems
Physics Olympiad problems are designed to challenge students' understanding of physics concepts and their ability to apply them in complex situations. They require a deep understanding and innovative approach.
- These problems emphasize critical thinking and problem-solving skills.
- They often combine multiple topics such as electromagnetism, mechanics, or thermodynamics.
- The key to success in tackling these problems is a solid grasp of fundamental principles, calculations, and sometimes creative intuition.
Other exercises in this chapter
Problem 53
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