Problem 54
Question
The binding energy per nucleon for magnesium- 27 is \(1.326 \times 10^{-12} \mathrm{J} /\) nucleon. Calculate the atomic mass of \(^{27} \mathrm{Mg}\) .
Step-by-Step Solution
Verified Answer
The atomic mass of magnesium-27 is approximately \(4.4335 * 10^{-26} kg\).
1Step 1: Calculate the total binding energy
First, we need to determine the total binding energy of magnesium-27. Since there are 27 nucleons in Mg-27, we can multiply the binding energy per nucleon by the number of nucleons:
Total binding energy = Binding energy per nucleon × Number of nucleons
Total binding energy = \(1.326 * 10^{-12} J/nucleon * 27\)
Total binding energy = \(3.5802 * 10^{-11} J\)
2Step 2: Calculate the mass defect
Next, we'll calculate the mass defect (i.e., the difference between the sum of nucleon masses and the atomic mass of magnesium-27) using the mass-energy equivalence formula:
Mass defect = Total binding energy / \(c^2\)
Mass defect = \(\frac{3.5802 * 10^{-11} J}{(3 * 10^8 m / s)^2}\)
Mass defect = \(3.989 * 10^{-28} kg\)
3Step 3: Calculate the atomic mass of magnesium-27
Now, we'll determine the atomic mass of magnesium-27 by adding the mass defect to the sum of the individual nucleon masses. Since magnesium has 12 protons and 15 neutrons, we need to account for their respective masses:
- Mass of proton = \(1.6726 * 10^{-27} kg\)
- Mass of neutron = \(1.6749 * 10^{-27} kg\)
Sum of nucleon masses = (12 * Mass of proton) + (15 * Mass of neutron)
Sum of nucleon masses = (\(12 * 1.6726 * 10^{-27} kg\)) + (\(15 * 1.6749 * 10^{-27} kg\))
Sum of nucleon masses = \(4.4733 * 10^{-26} kg\)
Now we can calculate the atomic mass of magnesium-27:
Atomic mass of Mg-27 = Sum of nucleon masses - Mass defect
Atomic mass of Mg-27 = \(4.4733 * 10^{-26} kg - 3.989 * 10^{-28} kg\)
Atomic mass of Mg-27 = \(4.4335 * 10^{-26} kg\)
Therefore, the atomic mass of magnesium-27 is approximately \(4.4335 * 10^{-26} kg\).
Key Concepts
Understanding Atomic MassExploring Mass DefectNucleons: The Building Blocks of the Nucleus
Understanding Atomic Mass
Atomic mass is a crucial concept when studying atoms and their components. It is essentially the mass of an atom, typically expressed in atomic mass units (amu) or kilograms for scientific calculations. An atomic mass unit is about one-twelfth the mass of a carbon-12 atom, which helps in comparing different elements.
To calculate the atomic mass of magnesium-27, we first need to understand that it includes the sum of the masses of its protons, neutrons, and electrons. However, since the mass of electrons is negligible compared to nucleons, they can be ignored in precision calculations.
To calculate the atomic mass of magnesium-27, we first need to understand that it includes the sum of the masses of its protons, neutrons, and electrons. However, since the mass of electrons is negligible compared to nucleons, they can be ignored in precision calculations.
- Atomic mass formula: It includes the masses of protons and neutrons in the nucleus.
- Calculation: For Mg-27, you would sum up 12 proton masses and 15 neutron masses, then adjust this value by the mass defect.
Exploring Mass Defect
Mass defect is an intriguing concept that explains why the sum of an atom's parts seems greater than its whole. It represents the apparent "loss" of mass when nucleons bind to form a nucleus. This difference manifests because some mass is converted to energy, the "binding energy," which holds the nucleus together.
This phenomenon is explained by Einstein's mass-energy equivalence principle, where the binding energy released can be expressed as a drop in mass:
This phenomenon is explained by Einstein's mass-energy equivalence principle, where the binding energy released can be expressed as a drop in mass:
- Calculate mass defect: Use the formula \( \text{Mass defect} = \frac{\text{Binding energy}}{c^2} \), where \( c \) is the speed of light.
- Importance: It helps to understand the stability of an atom; a greater mass defect generally means a more stable nucleus.
Nucleons: The Building Blocks of the Nucleus
Nucleons are the particles residing within an atom's nucleus, consisting of protons and neutrons. These particles are pivotal to the structure and stability of atoms.
The protons carry a positive charge, while neutrons are neutral. Their presence and ratio in the nucleus determine the identity and stability of an element.
The protons carry a positive charge, while neutrons are neutral. Their presence and ratio in the nucleus determine the identity and stability of an element.
- Protons: They determine the atomic number and thus the element's identity. For magnesium, 12 protons mean it is element number 12.
- Neutrons: These contribute to the mass of an atom and influence its stability; more neutrons can lead to isotope formation.
Other exercises in this chapter
Problem 51
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