Problem 54
Question
Solve each equation in by making an appropriate substitution. $$ (x-5)^{2}-4(x-5)-21=0 $$
Step-by-Step Solution
Verified Answer
The solutions to the equation are \(x = 12\) and \(x = 2\).
1Step 1: Define the Substitution
Identify the binomial \(x-5\) and replace it with another variable, say \(u\), so \(u = x - 5\). So the equation now becomes \(u^2 -4u - 21 =0\).
2Step 2: Apply the Quadratic Formula
Apply the quadratic formula \(u = [-b \pm \sqrt{b^2 - 4ac}] / 2a\) to solve for \(u\). With \(a = 1\), \(b = -4\), and \(c = -21\), this results in \(u = [4 \pm \sqrt{(-4)^2 - 4*1*(-21)}] / 2*1\). This simplifies to \(u = 7, -3\).
3Step 3: Solve for Original Variable
Substitute back \(u = x - 5\) into our result to find the original variable. Therefore, \(x = u + 5\). When \(u = 7\), \(x = 7 + 5 = 12\). When \(u = -3\), \(x = -3 + 5 = 2\).
Key Concepts
Quadratic EquationsQuadratic FormulaVariable Substitution
Quadratic Equations
Quadratic equations are polynomial equations of degree 2. They take the general form: Here, a, b, and c are constants, with a not equal to zero. The term ax² is the quadratic term, bx is the linear term, and c is the constant term. Since they involve squared terms, these equations frequently model situations involving area or any scenario that follows a path described by a parabola.
Solving quadratic equations can be done through various methods like factorization, completing the square, or using the quadratic formula. In our exercise, we initially face an equation that requires simplification using variable substitution to transform it into a clearer quadratic format.
This ability to recognize quadratic forms in disguised equations is crucial for simplifying the approach to solution.
Solving quadratic equations can be done through various methods like factorization, completing the square, or using the quadratic formula. In our exercise, we initially face an equation that requires simplification using variable substitution to transform it into a clearer quadratic format.
This ability to recognize quadratic forms in disguised equations is crucial for simplifying the approach to solution.
Quadratic Formula
The quadratic formula is a fundamental method for solving any quadratic equation. It is especially useful when factorization is challenging. The formula is written as:
In our example, after simplifying using substitution, the application of the quadratic formula aids in finding the solutions for the new variable.Step-by-step application ensures accurate results, transforming the math from abstract to concrete.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
In our example, after simplifying using substitution, the application of the quadratic formula aids in finding the solutions for the new variable.Step-by-step application ensures accurate results, transforming the math from abstract to concrete.
Variable Substitution
Variable substitution is a powerful technique in algebra to simplify complex equations. In the exercise at hand, we use this method by introducing a new variable, u. This reduces the complexity of the original equation, making it easier to work with.
Through the substitution of u = x - 5, the transformed quadratic equation \(u^2 - 4u - 21 = 0\) emerges. This reframing allows us to apply the quadratic formula more straightforwardly than directly solving for x.
Through the substitution of u = x - 5, the transformed quadratic equation \(u^2 - 4u - 21 = 0\) emerges. This reframing allows us to apply the quadratic formula more straightforwardly than directly solving for x.
- Identify a recurring binomial or expression.
- Substitute it with a symbol like u.
- Solve the resultant simpler equation.
- Re-substitute to solve for the original variable.
Other exercises in this chapter
Problem 53
Solve each inequality in Exercises 49-56 and graph the solution set on a number line. Express the solution set using interval notation. $$-11
View solution Problem 54
In Exercises \(54-56,\) perform the indicated operations and write the result in standard form. \((8+9 i)(2-i)-(1-i)(1+i)\)
View solution Problem 54
Solve each equation in Exercises \(39-54\) by completing the square. $$ 3 x^{2}-5 x-10=0 $$
View solution Problem 54
Including 8% sales tax, an inn charges $$ 162$ per night. Find the inn's nightly cost before the tax is added.
View solution