Problem 54
Question
Solve each equation. Check your solution. $$k-12=-40$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(k = -28\).
1Step 1: Isolate the Variable
We start by isolating the variable \(k\) on one side of the equation. The equation is \(k - 12 = -40\). We add 12 to both sides of this equation to get \(k = -40 + 12\).
2Step 2: Simplify the Equation
Next, we simplify the right side of the equation. Calculate the sum: \(-40 + 12 = -28\). Thus, the equation simplifies to \(k = -28\).
3Step 3: Check the Solution
To verify our solution, substitute \(k = -28\) back into the original equation \(k - 12 = -40\). Substitute to get \(-28 - 12 = -40\). Simplifying gives \(-40 = -40\), confirming our solution is correct.
Key Concepts
Understanding AlgebraIsolating VariablesChecking Solutions
Understanding Algebra
Algebra is a branch of mathematics that deals with symbols and the rules for manipulating those symbols. These symbols represent numbers and can be used to express relationships and solve equations. In algebra, you often work with equations to find the value of an unknown variable, like in the equation \(k - 12 = -40\). Here, \(k\) represents the unknown value that we need to solve for. By understanding algebra, you can create equations that model real-world situations, predict outcomes, and solve problems efficiently. Practicing these skills helps build a foundation for higher-level math courses and enhance logical thinking.
Isolating Variables
Isolating variables means getting a variable by itself on one side of the equation. This is the main strategy in solving algebraic equations. For the equation \(k - 12 = -40\), our first goal was to isolate the variable \(k\). To do this, we performed the inverse operation to cancel out the \(-12\) attached to \(k\).
- Identify the operation affecting the variable. Here, it's subtraction ( - 12).
- To undo this, we add 12 to both sides of the equation ( + 12).
Checking Solutions
Once you have a solution, it is important to verify its correctness by checking the solution. This involves substituting the value back into the original equation to see if it holds true.
For our solution, \(k = -28\), plugging it back into the original equation \(-28 - 12 = -40\) allows you to ensure that both sides of the equation are still equal:
For our solution, \(k = -28\), plugging it back into the original equation \(-28 - 12 = -40\) allows you to ensure that both sides of the equation are still equal:
- Substitute: Replace \(k\) with -28.
- Simplify: Perform the operation to verify both sides are equal.
- Conclusion: If both sides match, the solution is correct.
Other exercises in this chapter
Problem 54
Identify the algebraic expression that does not belong with the other three. Explain your reasoning. \(-6(x-2),\) \(x+12-7 x,\) \(-x-5 x+12,\) \(-6 x-12\)
View solution Problem 54
Divide. $$50 \div(-2)$$
View solution Problem 54
Solve each equation. Check your solution. $$5 y=60$$
View solution Problem 55
Find each product mentally. Example $$\begin{aligned}15 \cdot 12 &=15(10+2) \\\&=150+30 \text { or } 180\end{aligned}$$. $$8 \cdot 23$$
View solution