Problem 54
Question
Sketch the graph of each equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and radius. $$x^{2}+y^{2}=49$$
Step-by-Step Solution
Verified Answer
The graph is a circle with center at (0, 0) and radius 7.
1Step 1: Identify the Equation Type
The given equation is in the form of \( x^2 + y^2 = 49 \). This is the standard equation of a circle, which has no \(xy\) term and no linear terms such as \(x\) or \(y\).
2Step 2: Compare with Standard Form
In the standard form of a circle \( (x - h)^2 + (y - k)^2 = r^2 \), we identify: \(h = 0\), \(k = 0\), and \(r^2 = 49\). Thus, the circle is centered at \((0, 0)\) and has a radius \(r\).
3Step 3: Calculate the Radius
Since \(r^2 = 49\), we determine the radius \(r\) by taking the square root: \(r = \sqrt{49} = 7\).
4Step 4: Graph the Circle
To sketch the graph, plot the center of the circle at \((0, 0)\) and draw a circle with radius 7. It extends 7 units in all directions from the center.
Key Concepts
Standard Form of a CircleGraphing CirclesRadius and Center of a Circle
Standard Form of a Circle
The standard form of a circle is a way of representing the equation of a circle in the Cartesian coordinate system. It is given as \((x - h)^2 + (y - k)^2 = r^2\). In this formula:
For example, if your equation is \(x^2 + y^2 = 49\), you notice it doesn't have any \(h\) or \(k\). That means the center is at the origin \((0, 0)\), and we equate \(r^2 = 49\). The radius is found by taking the square root of 49, which is 7.
- \((h, k)\) denotes the center of the circle.
- \(r\) is the radius of the circle.
For example, if your equation is \(x^2 + y^2 = 49\), you notice it doesn't have any \(h\) or \(k\). That means the center is at the origin \((0, 0)\), and we equate \(r^2 = 49\). The radius is found by taking the square root of 49, which is 7.
Graphing Circles
Graphing circles may seem a bit challenging at first, but it's straightforward once you grasp how the equation relates to the graph. In a coordinate plane, a circle is perfectly round and symmetrical.
To graph a circle:
Graphing on paper might involve drawing a guide with a compass if you're working manually, but software tools often automate this process, making it easy to visualize circles precisely.
To graph a circle:
- Start by plotting the center of the circle as identified by \((h, k)\).
- From this central point, measure out the circle's radius \(r\) in all four cardinal directions: up, down, left, and right.
Graphing on paper might involve drawing a guide with a compass if you're working manually, but software tools often automate this process, making it easy to visualize circles precisely.
Radius and Center of a Circle
Understanding the radius and center of a circle is crucial in working with circle equations. The center, given by \((h, k)\) in the equation \((x-h)^2 + (y-k)^2 = r^2\), is the point from which every part of the circle is equally distant.
The radius \(r\) is the constant distance from the center to any point on the circle's edge. This distance determines the size of the circle:
The radius \(r\) is the constant distance from the center to any point on the circle's edge. This distance determines the size of the circle:
- A larger radius means a bigger circle.
- A smaller radius results in a smaller circle.
Other exercises in this chapter
Problem 53
Sketch the graph of each equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and radius. $$x^{2}+y^{2}=1$$
View solution Problem 54
Perform the indicated operations. \(\left(-5 x^{2}\right)\left(x^{2}\right)\)
View solution Problem 55
The graph of equation is an ellipse. Determine which distance is longer, the distance between the \(x\)-intercepts or the distance between the \(y\) -intercepts
View solution Problem 55
Sketch the graph of each equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and radius. $$x=(y+3)^{2}-1$$
View solution