Problem 54
Question
Simplify the expression and eliminate any negative exponents \((\mathrm{s}) .\) Assume that all letters denote positive numbers. \(\left(x^{-5} y^{3} z^{10}\right)^{-3 / 5}\)
Step-by-Step Solution
Verified Answer
\(\frac{x^3}{z^6 y^{\frac{9}{5}}}\)
1Step 1: Apply Power to a Power Rule
According to the power to a power rule, when raising a power to another power, we multiply the exponents. Start by applying this rule to each part of the expression: \( \left(x^{-5} y^{3} z^{10}\right)^{-\frac{3}{5}} \) becomes: \( x^{-5 \times -\frac{3}{5}} y^{3 \times -\frac{3}{5}} z^{10 \times -\frac{3}{5}} \).
2Step 2: Simplify the Exponents
Multiply the exponents: - For \(x\): \(-5 \times -\frac{3}{5} = 3\)- For \(y\): \(3 \times -\frac{3}{5} = -\frac{9}{5}\)- For \(z\): \(10 \times -\frac{3}{5} = -6\)
3Step 3: Rewrite with Positive Exponents
To eliminate negative exponents, rewrite the expression using positive exponents by flipping the terms: \(x^3 \cdot z^{-6} \cdot y^{-rac{9}{5}}\) becomes \(\frac{x^3}{z^6 y^{\frac{9}{5}}}\).
4Step 4: Present Simplified Expression
The final expression with positive exponents is: \(\frac{x^3}{z^6 y^{\frac{9}{5}}}\). This is the simplified form without any negative exponents.
Key Concepts
Negative ExponentsPower to a Power RuleExponentiation Rules
Negative Exponents
A negative exponent signals that the base, which the exponent is attached to, should be moved to the other side of the fraction line. This means that if the base with a negative exponent is in the numerator, it moves to the denominator, and vice versa. The base then appears with a positive exponent in its new position.
For instance, when you have an expression like \(x^{-5}\), this is equivalent to \(\frac{1}{x^5}\). Essentially, the negative sign in the exponent instructs us to "flip" the base to the other part of the fraction, converting the exponent to positive.
For instance, when you have an expression like \(x^{-5}\), this is equivalent to \(\frac{1}{x^5}\). Essentially, the negative sign in the exponent instructs us to "flip" the base to the other part of the fraction, converting the exponent to positive.
- \(a^{-b} = \frac{1}{a^b}\)
- \(\frac{1}{a^{-b}} = a^b\)
Power to a Power Rule
The power to a power rule is a fundamental principle in exponentiation that simplifies expressions involving exponents. When raising a power to another power, you multiply the exponents together. This rule helps in breaking down complex expressions easily.
For example, if you have \((a^m)^n\), according to the power to a power rule, it is simplified to \(a^{m \times n}\). This rule reduces the number of steps needed to solve or simplify exponential expressions by allowing simple multiplication of the exponents.
For example, if you have \((a^m)^n\), according to the power to a power rule, it is simplified to \(a^{m \times n}\). This rule reduces the number of steps needed to solve or simplify exponential expressions by allowing simple multiplication of the exponents.
- \((x^a)^b = x^{a \times b}\)
- \((x^{-a})^{-b} = x^{a \times b}\) because two negatives make a positive
Exponentiation Rules
Exponentiation rules are the cornerstone of operations involving powers and exponents in mathematics. These rules allow you to simplify expressions more efficiently.
Some of the essential rules include:
Some of the essential rules include:
- Multiplication of Bases with Same Exponents: \(a^m \times a^n = a^{m+n}\) - Here, you add the exponents while keeping the base the same.
- Division of Bases with Same Exponents: \(a^m \div a^n = a^{m-n}\) - When dividing, subtract the exponents.
- Zero Exponent Rule: \(a^0 = 1\) - Any base raised to the power of zero equals one.
- Negative Exponent Rule: See above.
Other exercises in this chapter
Problem 54
Perform the indicated operations and simplify. $$ \left(x^{2}+y-2\right)\left(x^{2}+y+2\right) $$
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31–76 ? Factor the expression completely. $$ \left(1+\frac{1}{x}\right)^{2}-\left(1-\frac{1}{x}\right)^{2} $$
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Write each number in scientific notation. $$ 129,540,000 $$
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\(55-64=\) Simplify the compound fractional expression. $$ \frac{\frac{x}{y}-\frac{y}{x}}{\frac{1}{x^{2}}-\frac{1}{y^{2}}} $$
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