Problem 54
Question
If \(x^{2}-(a+b+c) x+(a b+b c+c a)=0\) has imaginary roots, where \(a, b, c \in R^{+}\), then \(\sqrt{a}, \sqrt{b}, \sqrt{c}\) (A) can be the sides of a triangle (B) cannot be the sides of a triangle (C) nothing can be said (D) None of these
Step-by-Step Solution
Verified Answer
Option (B): Cannot be the sides of a triangle.
1Step 1: Examine the condition for imaginary roots
A quadratic equation has imaginary roots if its discriminant \(D\) is less than zero. The discriminant for the equation \(x^2 - (a+b+c)x + (ab+bc+ca) = 0\) is given by \((a+b+c)^2 - 4(ab+bc+ca)\). We need this discriminant to be less than zero for the roots to be imaginary.
2Step 2: Simplify the discriminant expression
Let's expand \((a+b+c)^2\) as \(a^2 + b^2 + c^2 + 2ab + 2bc + 2ca\). Subtract \(4(ab+bc+ca)\) from this, which yields the expression: \(a^2 + b^2 + c^2 + 2ab + 2bc + 2ca - 4ab - 4bc - 4ca = a^2 + b^2 + c^2 - 2ab - 2bc - 2ca\). This can be further simplified to \((a-b)^2 + (b-c)^2 + (c-a)^2\) which needs to be less than zero.
3Step 3: Apply conditions for a positive sum
Since \((a-b)^2 + (b-c)^2 + (c-a)^2\) involves squares, each term is non-negative. Therefore, for the entire sum \((a-b)^2 + (b-c)^2 + (c-a)^2\) to be less than zero, it is impossible unless all terms are zero, which implies \(a = b = c\).
4Step 4: Analyze the implications of equal terms
If \(a = b = c\), then \((a-b)^2 = (b-c)^2 = (c-a)^2 = 0\), and \((a,b,c)\) are not different, which implies that the squared parameters \((\sqrt{a}, \sqrt{b}, \sqrt{c})\) represent identical values that can indeed form a degenerate triangle (as they are equivalent sides of zero length). Thus, equality or mathematical constraints force the inequalities necessary for triangle inequality theorem failure. \(\sqrt{a}, \sqrt{b}, \sqrt{c}\) cannot be the sides of a non-degenerate triangle.
Key Concepts
Imaginary RootsQuadratic EquationsTriangle Inequality
Imaginary Roots
In the realm of complex numbers, imaginary roots are an interesting concept that often gets students scratching their heads. When we consider a quadratic equation, such as \[ x^2 - (a+b+c)x + (ab+bc+ca) = 0 \], it will have imaginary roots under a specific condition: when its discriminant \(D\) is less than zero. The discriminant is calculated as \[ D = (a+b+c)^2 - 4(ab+bc+ca) \]. Imaginary roots occur because the square root of a negative number is not defined in the real numbers, moving us into the complex numbers space, where these roots are evident.
- Imaginary roots indicate the quadratic does not intersect the x-axis.
- They are complex conjugates, with real parts being equal and imaginary parts having opposite signs.
Quadratic Equations
A quadratic equation enjoys a special place in mathematics. It is of the form \[ ax^2 + bx + c = 0 \], where 'a', 'b', and 'c' are constants and \( x \) represents an unknown variable.Quadratic equations are solved using methods like:
The discriminant of a quadratic equation determines the nature of its roots. For the equation \( ax^2 + bx + c = 0 \), if the discriminant \( b^2 - 4ac \) is:
- Factoring: Breaking down into simpler binomials.
- Completing the square: Reordering terms to form a perfect square binomial.
- Quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), a straightforward approach for any standard quadratic.
The discriminant of a quadratic equation determines the nature of its roots. For the equation \( ax^2 + bx + c = 0 \), if the discriminant \( b^2 - 4ac \) is:
- Positive, we have two distinct real roots.
- Zero, we have exactly one real root (or a repeated root).
- Negative, indicating two complex conjugate (imaginary) roots.
Triangle Inequality
The triangle inequality is a fundamental theorem in geometry. It states that for any triangle with sides of lengths \( a \), \( b \), and \( c \), the sum of the lengths of any two sides must be greater than the length of the remaining side.This can be represented as:
In the context of roots derived from quadratic equations, like \( \sqrt{a}, \sqrt{b}, \sqrt{c} \), the triangle inequality helps determine whether these computed values can serve as actual side lengths.When we find that they cannot fulfill the inequality conditions (as in the case of equating them like \( a = b = c \)), it becomes clear they can't form a non-degenerate triangle. Instead, they suggest a degenerate scenario or do not align as logical triangle sides. Thus, the triangle inequality acts as a validator for possible triangle formation scenarios.
- \( a + b > c \)
- \( b + c > a \)
- \( c + a > b \)
In the context of roots derived from quadratic equations, like \( \sqrt{a}, \sqrt{b}, \sqrt{c} \), the triangle inequality helps determine whether these computed values can serve as actual side lengths.When we find that they cannot fulfill the inequality conditions (as in the case of equating them like \( a = b = c \)), it becomes clear they can't form a non-degenerate triangle. Instead, they suggest a degenerate scenario or do not align as logical triangle sides. Thus, the triangle inequality acts as a validator for possible triangle formation scenarios.
Other exercises in this chapter
Problem 52
The equation \((x-n)^{m}+\left(x-n^{2}\right)^{m}+\left(x-n^{3}\right)^{m}+\ldots+\) \(\left(x-n^{m}\right)^{m}=0(m\) is odd positive integer \()\), has (A) all
View solution Problem 53
If \(f(x)=x-[x], x(\neq 0) \in R\), where \([x]\) is the greatest integer less than or equal to \(x\), then the number of solutions of \(f(x)+f\left(\frac{1}{x}
View solution Problem 56
If the roots of the equation \(x^{2}-2 a x+a^{2}+a-3=0\) are real and less than 3 , then (A) \(a4\)
View solution Problem 57
For all real \(x\), the minimum value of \(\frac{1-x+x^{2}}{1+x+x^{2}}\) is (A) 0 (B) \(\frac{1}{3}\) (C) 1 (D) 3
View solution