Problem 54
Question
Graph each equation. $$ y=-\frac{1}{x}\left(\text { Let } x=-2,-1,-\frac{1}{2},-\frac{1}{3}, \frac{1}{3}, \frac{1}{2}, 1, \text { and } 2 .\right) $$
Step-by-Step Solution
Verified Answer
To graph \(y=-\frac{1}{x}\), create a table using the provided x-values, calculate their corresponding y-values, and plot these points on the graph.
1Step 1: Create a Table of Values
Start by creating a table to represent the x-values and the corresponding y-values. The x-values have been provided (-2,-1,-1/2,-1/3,1/3,1/2,1,2). Set these up in a column in the table.
2Step 2: Calculate the Y-Values
Now, calculate the y-values by substituting each x-value into the equation \(y=-\frac{1}{x}\). For example, for \(x=-2\), \(y=-\frac{1}{-2}=0.5\). Compute the rest of the y-values similarly.
3Step 3: Plot the Values on the Graph
Once all x-values and y-values have been calculated, they can now be plotted on the graph. The graph of \(y=-\frac{1}{x}\) will be a hyperbola, and it should show the characteristic 'butterfly' shape when all points are connected.
Key Concepts
HyperbolaTable of ValuesCoordinate Plane Plotting
Hyperbola
When dealing with rational functions like the one in this exercise, it's helpful to understand the shape they take when graphed. The equation given, \( y = -\frac{1}{x} \), represents a type of curve called a hyperbola. In this case, the hyperbola has two separate branches that appear in opposite quadrants of the coordinate plane. This happens because the function is a rational one, with \( x \) in the denominator, which causes the graph to split into two distinct sections.
Hyperbolas are fascinating because they exhibit a specific symmetry. They have a vertical asymptote (a line that the graph approaches but never touches) and a horizontal asymptote. For \( y = -\frac{1}{x} \), the vertical asymptote is the \( y \)-axis (where \( x = 0 \)), and the horizontal asymptote is the \( x \)-axis (where \( y = 0 \)).
Hyperbolas are fascinating because they exhibit a specific symmetry. They have a vertical asymptote (a line that the graph approaches but never touches) and a horizontal asymptote. For \( y = -\frac{1}{x} \), the vertical asymptote is the \( y \)-axis (where \( x = 0 \)), and the horizontal asymptote is the \( x \)-axis (where \( y = 0 \)).
- Vertical Asymptote: This is where the graph can't be defined. As \( x \) gets very close to zero, \( y \) tends to infinity.
- Horizontal Asymptote: As \( x \) moves far to the left or right on the plane, \( y \) approaches zero.
Table of Values
Before plotting a function on a graph, it's crucial to understand how to construct a table of values. This is a straightforward method to visualize how the equation behaves for different \( x \) values by calculating the corresponding \( y \) values. For the equation \( y = -\frac{1}{x} \), we can use the given x-values to complete this process.
For each \( x \) value, plug it into the equation to find \( y \). The sign and magnitude of \( y \) indicate the position of each point on the graph. Let's explore this with a few examples:
For each \( x \) value, plug it into the equation to find \( y \). The sign and magnitude of \( y \) indicate the position of each point on the graph. Let's explore this with a few examples:
- For \( x = -2 \), \( y = -\frac{1}{-2} = 0.5 \).
- For \( x = 1 \), \( y = -\frac{1}{1} = -1 \).
- For \( x = 0.5 \), \( y = -\frac{1}{0.5} = -2 \).
Coordinate Plane Plotting
The process of plotting points on a coordinate plane is a fundamental skill in graphing rational functions. Once you've created your table of values and calculated the y-values, you're ready to transfer these points onto a graph.
To do this, start by plotting each point as an \((x, y)\) pair on the plane. Here’s how to make those calculations work:
To do this, start by plotting each point as an \((x, y)\) pair on the plane. Here’s how to make those calculations work:
- Locate each \( x \) value on the horizontal axis.
- Find the corresponding \( y \) value on the vertical axis.
- Mark the point where these two values intersect.
Other exercises in this chapter
Problem 54
Solve each compound inequality. $$-6
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By making an appropriate substitution. $$x+3 x^{\frac{1}{2}}-4=0$$
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Find all values of \(x\) satisfying the given conditions. \(y_{1}=\frac{x+1}{4}, y_{2}=\frac{x-2}{3},\) and \(y_{1}-y_{2}=-4\)
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Solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? $$A=lw \quad \text{for} \quad w$$
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