Problem 54
Question
For the following exercises, simplify each expression. $$ \sqrt{147 k^{3}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(7k\sqrt{3k}\).
1Step 1: Factor the Radicand
Begin by factoring the expression inside the square root, which is \( 147k^3 \).\[ 147 = 3 \times 49 = 3 \times 7^2 \]\[ k^3 = k^2 \times k \]This gives us:\[ \sqrt{147k^3} = \sqrt{3 \times 7^2 \times k^2 \times k} \]
2Step 2: Simplify the Radicand
Apply the property of square roots that \( \sqrt{a \times b} = \sqrt{a} \times \sqrt{b} \):\[ \sqrt{3 \times 7^2 \times k^2 \times k} = \sqrt{3} \times \sqrt{7^2} \times \sqrt{k^2} \times \sqrt{k} \]We can simplify further by taking the square roots of perfect squares:\[ = \sqrt{3} \times 7 \times k \times \sqrt{k} \]
3Step 3: Combine Simplified Terms
Combine the simplified terms into one expression:\[ \sqrt{147k^3} = 7k\sqrt{3k} \]
Key Concepts
Factoring RadicandsProperties of Square RootsPerfect Squares
Factoring Radicands
Factoring radicands is a crucial technique to simplify expressions under a square root. When you factor a radicand, you break it down into its prime factors or numbers that multiply together to give the radicand. For instance, to factorize \( 147 \), recognize that \( 147 = 3 \times 49 \) and \( 49 = 7^2 \), hence \( 147 = 3 \times 7^2 \). Similarly, if you have a variable, like \( k^3 \), think of it as \( k^2 \times k \).
- Decompose the number into prime factors.
- Compare all factors of the expression to identify potential perfect squares.
- Remember to handle both numeric and variable parts separately.
Properties of Square Roots
Understanding the properties of square roots is essential for simplifying expressions effectively. One of the key properties is that \( \sqrt{a \times b} = \sqrt{a} \times \sqrt{b} \). This property is particularly useful when dealing with square roots of products, as it allows the roots to be pulled apart.The property comes in handy when splitting the radicand into recognized perfect squares:
- If \( 49 = 7^2 \), then \( \sqrt{49} = 7 \).
- If \( k^2 \) is inside the square root, \( \sqrt{k^2} = k \).
Perfect Squares
Perfect squares are numbers or expressions that can be written as the square of an integer or another expression. Recognizing perfect squares within radicands can help simplify square roots. When you identify a perfect square, you can take its square root easily.
- Examples of perfect squares include \( 4, 9, 16, \text{ and } 25 \) because they are \( 2^2, 3^2, 4^2, \text{ and } 5^2 \) respectively.
- Within variables, \( k^2 \) is considered a perfect square because it is the square of \( k \).
Other exercises in this chapter
Problem 54
For the following exercises, perform the given operations and simplify. $$ \frac{x^{2}+x-6}{x^{2}-2 x-3} \cdot \frac{2 x^{2}-3 x-9}{x^{2}-x-2} \div \frac{10 x^{
View solution Problem 54
A prospective buyer wants to know how much grain a specific silo can hold. The area of the floor of the silo is \((2 x+9)^{2}\) . The height of the silo is \(10
View solution Problem 54
Perform the given operations and simplify. $$ \frac{x^{2}+x-6}{x^{2}-2 x-3} \cdot \frac{2 x^{2}-3 x-9}{x^{2}-x-2} \div \frac{10 x^{2}+27 x+18}{x^{2}+2 x+1} $$
View solution Problem 54
Simplify each expression. $$\sqrt{147 k^{3}}$$
View solution