Problem 54
Question
Find the exact distance between each pair of points. \((4,7),(-4,-5)\)
Step-by-Step Solution
Verified Answer
The exact distance is \(4\sqrt{13}\).
1Step 1: Identify the coordinates of the points
We have two points: Point A with coordinates \((x_1, y_1) = (4, 7)\) and Point B with coordinates \((x_2, y_2) = (-4, -5)\).
2Step 2: Apply the distance formula
To find the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\), use the distance formula: \[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]
3Step 3: Substitute the coordinates into the formula
Substitute the values from Step 1 into the distance formula: \[d = \sqrt{(-4 - 4)^2 + (-5 - 7)^2}\] which simplifies to: \[d = \sqrt{(-8)^2 + (-12)^2}\]
4Step 4: Calculate the squares of the differences
Calculate the squares inside the square root: \[(-8)^2 = 64 \quad \text{and} \quad (-12)^2 = 144\].
5Step 5: Add the calculated squares
Add the squared values: \[64 + 144 = 208\].
6Step 6: Take the square root
Take the square root of the sum to find the exact distance: \[d = \sqrt{208} = \sqrt{16 \times 13} = 4\sqrt{13}\].
7Step 7: Final Result
The exact distance between the points \((4,7)\) and \((-4,-5)\) is \(4\sqrt{13}\).
Key Concepts
Coordinate GeometryDistance Between PointsMathematical Problem Solving
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is the study of geometry using a coordinate system. This method allows us to describe geometric shapes numerically and derive algebraic equations to represent lines, curves, and figures.
In coordinate geometry, each point is specified by a pair of numerical coordinates. These coordinates, usually written as \(x, y\), represent the point's position on the Cartesian plane. This plane is divided into four quadrants by the x-axis (horizontal) and the y-axis (vertical).
Working within this system, you can easily calculate distances, gradients, and areas. By converting geometric problems into algebraic equations, coordinate geometry provides a powerful tool for mathematical problem solving.
In coordinate geometry, each point is specified by a pair of numerical coordinates. These coordinates, usually written as \(x, y\), represent the point's position on the Cartesian plane. This plane is divided into four quadrants by the x-axis (horizontal) and the y-axis (vertical).
Working within this system, you can easily calculate distances, gradients, and areas. By converting geometric problems into algebraic equations, coordinate geometry provides a powerful tool for mathematical problem solving.
Distance Between Points
One of the fundamental concepts in coordinate geometry is finding the distance between two points. The distance formula is derived from the Pythagorean theorem and applies to any two points in a plane.
The formula to find the distance \(d\) between two points with coordinates \(x_1, y_1\) and \(x_2, y_2\) is:
For example, for points \(4, 7\) and \(-4, -5\), the distance is calculated as \([(-4 - 4)^2 + (-5 - 7)^2]^{1/2}\), simplifying to \([64 + 144]^{1/2} = \sqrt{208} = 4\sqrt{13}\). This shows the power of coordinate geometry in solving problems easily with a standardized method.
The formula to find the distance \(d\) between two points with coordinates \(x_1, y_1\) and \(x_2, y_2\) is:
- \[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]
For example, for points \(4, 7\) and \(-4, -5\), the distance is calculated as \([(-4 - 4)^2 + (-5 - 7)^2]^{1/2}\), simplifying to \([64 + 144]^{1/2} = \sqrt{208} = 4\sqrt{13}\). This shows the power of coordinate geometry in solving problems easily with a standardized method.
Mathematical Problem Solving
Mathematical problem solving involves a variety of skills and habits of thought that enable tackling diverse problems.
To solve problems like finding the distance between points, it's crucial to:
To solve problems like finding the distance between points, it's crucial to:
- Understand the problem and identify what is given.
- Select an appropriate strategy or formula. For example, using the distance formula for coordinate geometric problems.
- Execute calculations carefully and accurately.
- Reflect on the solution to ensure its reasonableness and clarity.
Other exercises in this chapter
Problem 53
Solve each equation. $$ (34 x+26)^{1 / 3}=4(x-1)^{1 / 3} $$
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Square or cube each quantity and simplify the result. $$ (\sqrt{5 x}-\sqrt{3})^{2} $$
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Multiply. Write all answers in the form \(a+b i .\) See Example 5 \(i(8+2 i)\)
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Simplify by combining like radicals. $$ 11 \sqrt{3}+2 \sqrt{3} $$
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