Problem 54
Question
Find the domain of the function. Then sketch its graph and find the range. $$y=\sqrt{3 x+1}$$
Step-by-Step Solution
Verified Answer
The domain of the function \(y=\sqrt{3 x+1}\) is \([-1/3, \infty)\), the range is \([0, \infty)\), and the graph is a sideways parabola starting at point (-1/3, 0) and increasing as x increases.
1Step 1: Find the Domain
In order to find the domain of the function, which is the set of all possible x-values, set the expression inside the square root \(3 x+1\) to be greater than or equal to 0: \[3 x+1 \geq 0 \]Solving this, one gets \(x \geq -1/3\). So the domain of the function \(y=\sqrt{3 x+1}\) is \([-1/3, \infty)\)
2Step 2: Sketch the Graph
The square root function starts from -1/3 (due to the domain derived from step 1) and continue upwards, as the square root of a number is positive. This graph represents half of a parabola turned on its side. At x = -1/3, y = 0; as values for x increase, y also increases. You can plot the points (-1/3, 0), (0, 1) and (1, 2) to get the general shape of the graph.
3Step 3: Find the Range
The range of a function is the set of all possible values of the output (y). This function will output all y-values greater than or equal to zero, since x is greater than or equal to -1/3. Hence, the range of the function is \([0, \infty)\)
Key Concepts
range of a functiongraphing functionssquare root functions
range of a function
In mathematics, the range of a function is a critical concept that refers to all possible output values (y-values) a function can produce. To understand the range of the function \(y=\sqrt{3x+1}\), we need to examine how the values of \(x\) affect the values of \(y\).
Here's how you can determine the range:
Here's how you can determine the range:
- Firstly, consider the operation involved: a square root. By definition, the square root function \(\sqrt{a}\) is only defined for \(a \geq 0\), and its outputs are non-negative.
- For \(y=\sqrt{3x+1}\), when \(x\) is at its minimum value of \(-1/3\), we substitute into the equation to find \(y=0\).
- As \(x\) increases beyond \(-1/3\), \(3x+1\) becomes positive and larger, making the square root increase further.
graphing functions
Graphing functions is a visual representation of how a function behaves. For the function \(y=\sqrt{3x+1}\), graphing it helps understand its domain and range better.
Here are some steps to make the graph:
Here are some steps to make the graph:
- Identify the domain: We already found that \(x\) must be greater than or equal to \(-1/3\). Hence, our graph only exists for these x-values.
- Find key points: Calculate a few values to plot on the graph for clarity. When \(x = -1/3\), \(y = 0\). When \(x = 0\), \(y = 1\), and for \(x = 1\), \(y = \sqrt{3}\approx 1.73\).
- Plot these points on a coordinate plane.
square root functions
Square root functions are a type of radical function, with the square root symbol \(\sqrt{ }\), and they often present unique graph shapes and characteristics.
Understanding their behavior involves:
Understanding their behavior involves:
- This function, \(y=\sqrt{3x+1}\), has the expression inside the square root \(3x+1\). The square root requires this to be non-negative, which defines the domain \(x\geq -1/3\).
- The output is always non-negative because the square root of any real number is positive, covering the range \([0, \infty)\).
- Graphically, these functions start from a point depending on the domain and rise steadily, never decreasing, as the value under the root increases.
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