Problem 54
Question
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(t-2)\left(t^{2}+7 t+2\right)$$
Step-by-Step Solution
Verified Answer
The product is \(t^3 + 5t^2 - 12t - 4\).
1Step 1: Review the Distributive Property
To solve the product \((t-2)(t^2 + 7t + 2)\), we can use the distributive property which states that \(a(b+c) = ab + ac\). This property will allow us to distribute each term from the binomial across each term in the trinomial.
2Step 2: Distribute Each Term
1. Distribute the first term \(t\) from \(t-2\):- \(t(t^2) = t^3\)- \(t(7t) = 7t^2\)- \(t(2) = 2t\)2. Distribute the second term \(-2\) from \(t-2\):- \(-2(t^2) = -2t^2\)- \(-2(7t) = -14t\)- \(-2(2) = -4\)
3Step 3: Combine Like Terms
Now, combine all the terms:- The \(t^3\) term is alone: \(t^3\)- Combine the \(t^2\) terms: \(7t^2 - 2t^2 = 5t^2\)- Combine the \(t\) terms: \(2t - 14t = -12t\)- The constant term is: \(-4\)The expression now is: \(t^3 + 5t^2 - 12t - 4\).
Key Concepts
The Distributive PropertyCombining Like TermsSpecial Product Patterns
The Distributive Property
The distributive property is a fundamental principle in mathematics used to simplify expressions. It's especially handy when you're dealing with multiplication involving polynomials. In this context, we use the distributive property to expand expressions like
- Multiply each term in one polynomial by every term in another polynomial
- Represent expressions in an expanded form
- The first term \(t\) in \((t-2)\) multiplies each term in \((t^2 + 7t + 2)\), resulting in three products: \(t^3, 7t^2,\) and \(2t\)
- The second term \(-2\) in \((t-2)\) also multiplies each term in \((t^2 + 7t + 2)\), yielding: \(-2t^2, -14t,\) and \(-4\)
Combining Like Terms
Once you've expanded the polynomial expression using the distributive property, the next logical step is to combine like terms. Like terms are terms that have the same variable raised to the same power.In our example, after distributing the terms, the expression becomes: \(t^3 + 7t^2 + 2t - 2t^2 - 14t - 4\).Now, it's time to combine them:
- The \(t^3\) term stands alone and cannot be combined with any other terms.
- For the \(t^2\) terms: Combine \(7t^2\) and \(-2t^2\) to get \(5t^2\).
- For the \(t\) terms: Combine \(2t\) and \(-14t\) to get \(-12t\).
- Finally, the constant term is \(-4\) and remains unchanged.
Special Product Patterns
Special product patterns are shortcuts that can be used to quickly expand binomial expressions without having to apply distribution in the traditional way. These patterns are derived from basic algebraic identities. However, sometimes, especially with more complex polynomials like our case, traditional distribution and combining like terms is more straightforward.The most common special product patterns include:
- The square of a binomial: \((a + b)^2 = a^2 + 2ab + b^2\)
- The difference of squares: \((a + b)(a - b) = a^2 - b^2\)
Other exercises in this chapter
Problem 54
Use the sum-of-two-cubes or the difference-of-two-cubes pattern to factor each of the following. $$125 x^{3}+27 y^{3}$$
View solution Problem 54
Factor by grouping. $$3 b x+3 x+b y+y$$
View solution Problem 54
Raise each monomial to the indicated power. $$-\left(x y^{2} z^{3}\right)^{8}$$
View solution Problem 54
Perform the indicated operations. $$\left(-6 x^{2}+2 x+5\right)-\left(4 x^{2}+4 x-1\right)+\left(7 x^{2}+4\right)$$
View solution